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kakasveta [241]

1 year ago

7

When measuring distance 12 beads are approximately equat to 6 erasers. how many erasers are equal to 18 beads? How many beads ar

e equal to 42 erasers?

1 answer:

hammer [34]1 year ago

5 0

Answer:

9 and 42

Step-by-step explanation:

12b = 6e ➡ 2b = 1e (b : beads, e : eraser)

we can conclude from the equation we created that the ratio of bead to eraser is 1/2

therefore 18b = 9e

and

42 × 2 =84

84b = 42e

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In Martian Poker, the game is played with 8 cards drawn from a 52 card deck.

WITCHER [35]

Step-by-step explanation:

In Martian Poker, the game is played with 8 cards drawn from a 52 card deck.

What is the probability of a Martian drawing “two trips and a pair". They get 2

three of a kinds and a pair.

6 0

1 year ago

Se tiene una pirámide regular cuadrangular cuyas caras laterales forman con la base un angulo que mide 53º y el area de la super

SIZIF [17.4K]

Answer:

La altura de la pirámide es de 8.14 unidades.

Step-by-step explanation:

Hay una pirámide cuadrangular regular cuyas caras laterales forman un ángulo que mide 53º con la base y el área de la superficie lateral es 60. ¿Qué altura tiene?

Dado que el área de superficie lateral = 60

Tenemos

Área del triángulo equilátero = (√3 / 4) × a²

(√3 / 4) × a² = 60

a² = 60 / (√3 / 4) = 80 · √3

a = √ (80 · √3) = 11.77 unidades

La altura inclinada = Altura de la superficie inclinada = a × sin (60) = 11.77 × sin (60)

La altura inclinada = 11.77 × sin (60) = 10.194 unidades

La altura de la pirámide = Altura inclinada × sin (ángulo de caras laterales con la base)

La altura de la pirámide = 10.194 × sin (53) = 8.14 unidades.

La altura de la pirámide = 8.14 unidades.

8 0

2 years ago

Imagine you are a financial analyst at an investment bank. According to your research of publicly-traded companies, 60% of the c

lilavasa [31]

Answer:

0.0667 = 6.67% probability that the shares of a company that fires its CEO will increase by more than 5%.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

Event A: Company fires the CEO

Event B: Shares increase by more than 5%.

Probability of a company firing it's CEO:

35% of 100 - 4 = 96%(shares did not increase by more than 5%).

60% of 4%(shared did increase by more than 5%).

So

$P(A) = 0.35*0.96 + 0.6*0.04 = 0.36$

Intersection of events A and B:

Fires the CEO and shared increased by more than 5%, is 60% of 4%. So

$P(A \cap B) = 0.6*0.04 = 0.024$

Probability that the shares of a company that fires its CEO will increase by more than 5%.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.024}{0.36} = 0.0667$

0.0667 = 6.67% probability that the shares of a company that fires its CEO will increase by more than 5%.

5 0

1 year ago

Suppose that Kevin can choose to get home from work by car or bus. When he chooses to get home by car, he arrives home after 7 p

astraxan [27]

Answer:

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = 0.838

Step-by-step explanation:

Let the probability that Kevin arrives home after 7 pm be P(L)

Probability that Kevin uses the bus = P(B)

Probability that Kevin uses the car = P(C)

Probability of arriving home after 7 pm if the car was taken = P(L|C) = 4% = 0.04

Probability of arriving home after 7 pm if the bus was taken = P(L|B) = 15% = 0.15

The bus is cheaper, So, he uses the bus 58% of the time.

P(B) = 58% = 0.58

P(C) = P(B') = 1 - P(B) = 1 - 0.58 = 0.42

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = P(B|L)

The conditional probability P(A|B) is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

Hence, the required probability, P(B|L) is given as

P(B|L) = P(B n L) ÷ P(L)

But we do not have any of P(B n L) and P(L)

Although, we can obtain these probabilities from the already given probabilities

P(L|C) = 0.04

P(L|B) = 0.15

P(B) = 0.58

P(C) = 0.42

P(L|C) = P(L n C) ÷ P(C)

P(L n C) = P(L|C) × P(C) = 0.04 × 0.42 = 0.0168

P(L|B) = P(L n B) ÷ P(B)

P(L n B) = P(L|B) × P(B) = 0.15 × 0.58 = 0.087

P(L) = P(L n C) + P(L n B) = 0.0168 + 0.087 = 0.1038 (Since the bus and the car are the two only options)

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm

= P(B|L) = P(B n L) ÷ P(L)

P(B n L) = P(L n B) = 0.087

P(L) = 0.1038

P(B|L) = (0.087/0.1038) = 0.838150289 = 0.838

Hope this Helps!!!

8 0

1 year ago

We have k coins. The probability of Heads is the same for each coin and is the realized value q of a random variable Q that is u

nata0808 [166]

Answer:

Step-by-step explanation:

The question is not in correct order ; so the first thing we are required to do is to put them together in the right form to make it easier to proof; having said that. let's get started!.

From the second part " You may find the following integral useful: For any non-negative integers k and m,"

The next equation goes thus : $\int\limits^1_0 \ \ q^k (1-q)^m dq = \frac{k!m!}{(k+m+1)!}$

a. Find the PMF of $T_1$ . (Express your answer in terms of t using standard notation.)

For t=1,2…,

$p_T_1$ (t)= $\frac{1}{(t*(t*1))}$ by using conditional probability to solve PMF

b) Find the least mean squares (LMS) estimate of Q based on the observed value, t, of T1. (Express your answer in terms of t using standard notation.)

By using the mathematical definition of integration to solve the estimate of Q:

$E|Q|T_1=t|= \frac{2}{t+2}$

c) We flip each of the k coins until they result in Heads for the first time. Compute the maximum a posteriori (MAP) estimate q^ of Q given the number of tosses needed, T1=t1,…,Tk=tk, for each coin.

The MAP estimate of q is :

$\bar q = \frac{k}{\sum^k_{i=1}}t_i$

3 0

1 year ago