Answer:
c. 
Step-by-step explanation:
Given,
Number of bacterias who alive for at least 30 days = 5,
Bacterias who alive for 2 days = 10,
Died bacterias = 10,
Total bacterias = 5 + 10 + 10 = 25,
Ways of choosing a bacteria =
=
= 25,
While, ways of choosing of a bacteria who will live after 1 week =
=
= 5,
Hence, the probability it will still be alive after one week =
= 
OPTION C is correct.
Answer:
The best estimate solution to the system of equations is (0, 3)
Step-by-step explanation:
we have
y=14x-2 ------> equation A
y=-2x+3 -----> equation B
Solve the system by elimination
Multiply the equation B by 7 both sides
(7)y=(7)(-2x+3)
7y=-14x+21 -------> equation C
Adds equation A and equation C
y=14x-2
7y=-14x+21
-----------------
y+7y=-2+21
8y=19
y=19/8
Find the value of x
y=14x-2
19/8=14x-2
19=112x-16
112x=19+16
112x=35
x=35/112
so
The solution is the point (35/112,19/8)
Convert to decimal number
(0.3125,2.375)
therefore
The best estimate solution to the system of equations is (0, 3)
Answer:
Step-by-step explanation:
(a)
Total cost = (7 items * Cost per item) + Shipping fee = 7*6.5 + 8.5 = $54
(b)
Modelling the above equation with symbols:
c = s*6.5 + 8.5 = 6.5s + 8.5
(c)
For a total cost of 80$, c = 80:
80 = 6.5s + 8.5
Calculating, we get:
s = 11 items
Rachel ordered a total of 11 items
Answer:
ten thousands/thousands/hundreds/tens/ones
7 / 0 / 0 / 0 / 0
Explanation:
10 x 7,000 = 70, 000
For a set of data: x = (0,1,2,3,4,5,6) and y=(36, 28, 25, 24, 23, 21, 19), is it wise to use a linear regression to extrapolate
melisa1 [442]
Answer:
The problem with this solution is that a regression model is not recommended to extrapolate because we do not know if the linear relation that we calculated for a specific range of x values still holds outside this range.
Step-by-step explanation:
We have a linear regression model, with a range of the independent variable "x" that goes from 0 to 6.
The regression model finds a good fit (r=0.8582).
As it has a good fit, it is proposed to use this model to extrapolate and calculate the value of y for x=50.
It is not recommended to extrapolate a regression model unless we are really sure that the model is still valid within the range within we are extrapolating.
This means that if we have no proof that y has a linear relation in a range of x that includes x, the extrapolation has no validity and can lead to serious errors.
A linear regression model is only suitable for interpolation or extrapolating within the range we are sure that the relation between y and x is linear within a certain acceptable error.