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serg [7]
2 years ago
10

Next month, Tokuji's monthly net income will increase to

Mathematics
1 answer:
shepuryov [24]2 years ago
7 0

The correct answer on Edge is A: $20

Hope I could help!!

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A meter is 3.37 inches more than a yard swimmer a swims 100 meters and swimmer b swims 100 yeards how many more feet did swimmer
olga_2 [115]
Swimmer a swims 100 meters, which is 100 1-meters, which is 100
(1 yards +3.37 inches) = 100 yards + 337 inches.

1 yard is 3 feet, so 100 yards are 300 feet.

100 in is 8.33 feet so
337 in is (337*8.33)/100=28.07 feet


Swimmer b swims 100 yards, which is 300 feet

Swimmer a swam 28.07 feet.


4 0
2 years ago
One year ago, Lindsey deposited $250 into a savings account. Her balance is now $253. Two years ago, Jenn deposited $250 into a
ipn [44]

Answer:

Jenn simple interest was 1.5% annually making Jenns account have the highest interest rate.

Step-by-step explanation:

4 0
1 year ago
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Using the U- Substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to ...
AleksAgata [21]
We will use u-substitute:u= \sqrt{2x} , \frac{du}{dx}= \frac{1}{ \sqrt{2x} }= \frac{1}{u}Then for substitution:dx=u du. and integral becomes:\int { \frac{u}{u+1} } \, du = \int { \frac{u+1-1}{u+1} } \, du= \int{1} \, du- \int { \frac{1}{u-1} } \, dx=u-ln(u+1)=\sqrt{2x}-ln( \sqrt{2x}+1). Now we will change the values of limits: \sqrt{16}-ln( \sqrt{16}+1)-( \sqrt{4}-ln( \sqrt{4}+1))=4-ln(5)-2+ln(3)=2+ln(0,6)=2-0.51=1.49

8 0
2 years ago
A randomized study compared two different systems for tracking baggage at an airport. The treatment group using System A reporte
Natasha2012 [34]

Answer:

D. The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

Step-by-step explanation:

The treatment group using System A reported a mean of 18.5 lost bags per day. The treatment group using System B reported a mean of 16.6 lost bags per day.

The best conclusion that can be made is - The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

As we know, in statistics, nothing happens by chance. So, this option is correct.

8 0
2 years ago
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Members of a school club are buying matching shirts. They know at least 25 members will get a shirt. Long-sleeved shirts are $10
charle [14.2K]

Answer:

Maximum number of long sleeved shirt that can be purchase is, 8

and

Minimum number of long sleeved shirt that can be purchased is, 0

Step-by-step explanation:

let y represents the number of short sleeves  and x represents the number of long sleeves.

As per the given condition:

Members of a school club are buying matching shirts. They know at least 25 members will get a shirt.

we have;

x+y\geq 25              or

y\geq 25 -x    ....[1]

Since, long sleeves shirt are $ 10 each and short sleeves shirt are $ 5 each.

then;

Total cost of long sleeves is 10x and

the total cost of short sleeves is 5y

Also; the club can spend no more than $ 165

then;

10x+5y\leq 165                  

 5y\leq 165 -10x or

y\leq 33-2x ......[2]

Solving the inequality equation with the graph :

Plot equation [1] and [2]; we get the maximum at point (8 , 17)

so, x= 8.

If we take minimum value of x =0 then y is between 25 and 33.

so, the solution area is between the lines to the left of where the lines intersect.

Therefore, the maximum number of long sleeved shirts can be purchased is 8 and the minimum number of long sleeved shirt can be purchased is 0






6 0
2 years ago
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