Answer:
<h2>It takes 36 minutes to fill the bathtub using just hot water.</h2>
Step-by-step explanation:
We are gonna name V the complete volume of the bathtub, which is filled a certain amount of minutes. Each filling rate or speed is gonna be expressed as:
.
So, if we apply this consideration to each case we have:
Using cold and hot water: 
Using only cold water: 
Using only hot water:
; because we don't knot the time it takes to fill the bathtub with hot water.
Now, as you can see, Cold and Hot water is a sum of cold water only and hot water only:

Solving the equation for <em>x: </em>

Therefore, it takes 36 minutes to fill the bathtub using just hot water.
Answer:
A. 9.85 inches
Step-by-step explanation:
In the graph we can see that 1 month has a rainfall of 0.4 in, 2 months have a rainfall of 0.5 in, 1 month has a rainfall of 0.6 in, 2 months have a rainfall of 0.85 in, 1 month has a rainfall of 0.95 in, 2 months have a rainfall of 1.0 in, 2 months have a rainfall of 1.05 in and 1 month has a rainfall of 1.1 in.
The total amount of rainfall in the desert that year was: 0.4 + 2*0.5 + 0.6 + 2*0.85 + 0.95 + 2*1.0 + 2*1.05 + 1.1 = 9.85 inches
14 - 9 = 5
19 - 14 = 5
24 - 19 = 5
29 - 24 = 5
It is an arithmetic sequence with differences, b = 5 and a = 9
a(n) = a + b(n - 1)
a(n) = 9 + 5(n - 1)
The answer is B
9^ ? 3^2 + 7^2
81 ? 9 + 49
81 > 58
c^ > a^2 + b^2
answer is obtuse triangle
Answer:
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Step-by-step explanation:
The options are missing; However, I'll simplify the given expression.
Given
![\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B32x%5E3y%5E6%7D%7D%7B%5Csqrt%5B3%5D%7B2x%5E9y%5E2%7D%20%7D)
Required
Write Equivalent Expression
To solve this expression, we'll make use of laws of indices throughout.
From laws of indices ![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
So,
gives

Also from laws of indices

So, the above expression can be further simplified to

Multiply the exponents gives

Substitute
for 32


From laws of indices

This law can be applied to the expression above;
becomes

Solve exponents


From laws of indices,
; So,
gives

The expression at the numerator can be combined to give

Lastly, From laws of indices,
; So,
becomes
![\frac{\sqrt[3]{(2y)}^{4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B%282y%29%7D%5E%7B4%7D%7D%7Bx%5E2%7D)
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Hence,
is equivalent to ![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)