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My name is Ann [436]
2 years ago
14

Which of the following companies offers the greatest total employment compensation? Company A Company B Company C Company D Gros

s Pay $37,600 $36,800 $38,100 $39,000 Paid insurance $2,800 $2,400 $2,100 $1,800 Paid time off $3,100 $3,600 $2,900 $2,500 Job expenses $1,200 $600 $300 $800 a. Company A b. Company B c. Company C d. Company D
Mathematics
2 answers:
san4es73 [151]2 years ago
8 0

we know that

To find the company with the greatest total employee compensation package, adds each company's gross pay, paid insurance, and paid time off, then subtract the job expenses on the sum

So

Find the total employee compensation package for each company

Step 1

Find the total employee compensation package for company A

total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses

total\ employee\ compensation=37,600+2,800+3,100-1,200\\ total\ employee\ compensation=42,300\ dollars

Step 2

Find the total employee compensation package for company B

total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses

total\ employee\ compensation=36,800+2,400+3,600-600\\ total\ employee\ compensation=42,200\ dollars

Step 3

Find the total employee compensation package for company C

total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses

total\ employee\ compensation=38,100+2,100+2,900-300\\ total\ employee\ compensation=42,800\ dollars

Step 4

Find the total employee compensation package for company D

total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses

total\ employee\ compensation=39,000+1,800+2,500-800\\ total\ employee\ compensation=42,500\ dollars

therefore

the answer is

the company with the greatest total employee compensation package is the company C

balu736 [363]2 years ago
5 0

Answer:

C

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We are gonna name V the complete volume of the bathtub, which is filled a certain amount of minutes. Each filling rate or speed is gonna be expressed as: \frac{V}{t}.

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Using cold and hot water: \frac{V}{12}

Using only cold water: \frac{V}{18}

Using only hot water: \frac{V}{x}; because we don't knot the time it takes to fill the bathtub with hot water.

Now, as you can see, Cold and Hot water is a sum of cold water only and hot water only:

\frac{V}{12}=\frac{V}{18}+\frac{V}{x}

Solving the equation for <em>x: </em>

\frac{V}{12}=\frac{xV+18V}{18x} \\\frac{V}{12}=\frac{(x+18)V}{18x}\\\\\frac{18xV}{V}=12(x+18)\\18x=12x+216\\18x-12x=216\\6x=216\\x=\frac{216}{6}=36

Therefore, it takes 36 minutes to fill the bathtub using just hot water.

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which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater
Nutka1998 [239]

Answer:

\frac{\sqrt[3]{16y^4}}{x^2}

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices \sqrt[n]{a}  = a^{\frac{1}{n}}

So,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } gives

\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}

Also from laws of indices

(ab)^n = a^nb^n

So, the above expression can be further simplified to

\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}

Multiply the exponents gives

\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

Substitute 2^5 for 32

\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

From laws of indices

\frac{a^m}{a^n} = a^{m-n}

This law can be applied to the expression above;

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})} becomes

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Solve exponents

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From laws of indices,

a^{-n} = \frac{1}{a^n}; So,

2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}} gives

\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}

The expression at the numerator can be combined to give

\frac{(2y)^{\frac{4}{3}}}{x^2}

Lastly, From laws of indices,

a^{\frac{m}{n} = \sqrt[n]{a^m}; So,

\frac{(2y)^{\frac{4}{3}}}{x^2} becomes

\frac{\sqrt[3]{(2y)}^{4}}{x^2}

\frac{\sqrt[3]{16y^4}}{x^2}

Hence,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } is equivalent to \frac{\sqrt[3]{16y^4}}{x^2}

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