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labwork [276]
2 years ago
12

Connor has seven more nickels than dimes and twice as many quarters as dimes. If he has $6.20, how many nickels does he have?

Mathematics
1 answer:
Novosadov [1.4K]2 years ago
8 0
Connor has 16 nickels. If you have 9 dimes (90 cents) and you doubled it that would give you 18 quarters ($4.50). you have 7 more nickels than dimes, so you do 7+9 which equals 16 nickels (80 cents). 90+450+80=620.
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Suppose you have just enough money, in coins, to pay for a gallon of milk priced at $2.40. You have 12 coins, all quarters and d
wel
The answer is
q + d = 12
0.25q + 0.10d = 2.40


q - the number of quarters
d - the number of dimes

You have 12 <span>coins, all quarters and dimes:
q + d = 12

The value of 1 quarter is $0.25.
The value of 1 dime is $0.10.
Therefore, if you want to pay </span>$2.40 you will have q quarters of value $0.25(0.25q) and d dimes of value $0.10d (0.10d).
The second equation is:
0.25q + 0.10d = 2.40
3 0
2 years ago
Which of the following values are in the range of the function graphed below?
Elanso [62]
Hello!

The range is all of the y-values of the function. As we can see, the function is at y-values 0, -2,-4 and -6.

Therefore, our answers are 0 ,-2 and -6.

I hope this helps!
4 0
2 years ago
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7. Classical linear model assumptions for time series Consider the following stochastic process {(x1, x2, x3, . . . , xk, yt): t
iogann1982 [59]

Answer:

Options are missing.

The options for the above question are:

TS.1: Linear in parameters.

TS.2:No perfect collinearity

TS.3: Zero conditional mean.

TS.4: Homoskedasticity.

TS.5: No serial correlation

TS.6: Normality.

Hence the correct answer is TS1 to TS 5

Step-by-step explanation:

Assumptions TS 1 to TS 5 are the minimum set of assumptions needed to for the OLS estimates to be the best linear unbiased estimators conditional on explanatory variables for all time periods.

The assumptions of Normality is not needed for the estimators to show the BLUE property

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2 years ago
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Paraphin [41]

Answer:

yes

Step-by-step explanation:

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Which sets of numbers contain whole numbers? Check all that apply. Negative 2 and StartFraction 5 Over 6 EndFraction, negative 5
Zigmanuir [339]

Answer:

The whole numbers are 0 and 79.

Step-by-step explanation:

The numbers provided are as follows:

-2\frac{5}{6},\ -54,\ -4,\ -57,\ -89,\ 79,\ \frac{6}{9},\ \\\\-19\frac{2}{3},\ \frac{2}{4},\ 0,\ \frac{2}{7},\ -3,\ -2, -7,\ -8,\ \\\\\frac{1}{8},\ -\frac{4}{8},\ 1\frac{3}{8},\ -\frac{7}{8}

Whole numbers are a set of natural positive numbers and 0. This set basically consists of counting discrete numbers.

Such as: 0, 1, 2, 3, 4, 5....

From the provided set of numbers the whole numbers are:

S = {79 and 0}

Thus, the whole numbers are 0 and 79.

8 0
2 years ago
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