The relative frequencies, from least to greatest, would be:
The percentage of all entries painted by Art 1 students (14.33%), the percentage of Art 2 entries that were digital (22.02%), and the percentage of clay entries done by Art 3 students (25.32%).
Explanation
The percentage of clay entries done by Art 3 students: There are 20 clay entries done by Art 3 students, out of 79 clay entries; 20/79 = 25.32%
The percentage of all entries painted by Art 1 students: There are 43 entries painted by Art 1 students out of 300 total; 43/300 = 14.33%
The percentage of Art 2 entries that are digital: There are 24 Art 2 digital entries out of 109 total Art 2 entries; 24/109 = 22.02%
Thank you for your question!
In order to get the cost of 1 kg of cabbage, divide the cost by the quantity:
1.20/2.5
0.48
Now, multiply the amount for 1 kg to 3.75, because you need 3.75 times the amount.
0.48 * 3.75
1.80
So, it would cost 1.80 pounds for 3.75 kg.
Hope this helped!
Answer:
She traveled a total of 2875 metres during practice.
Step-by-step explanation:
Doris ran 2.5 kilometres, then sprinted 300 meters and finally walked 1/4 of the distance she sprinted.
To find the total distance that she traveled, we simply add the distance that she ran, sprinted and walked.
We will convert all distances to metres.
She ran 2.5 kilometres:
1 km = 1000 m
2.5 km = 2.5 * 1000 = 2500 m
So, she ran 2500 m.
She sprinted 300 m.
Se walked 1/4 the distance that she sprinted:
1/4 * 300 = 75 m
She walked 75 m.
Therefore, the total distance she traveled is:
2500 + 300 + 75 = 2875 m
She traveled a total of 2875 metres during practice.
Answer:

Step-by-step explanation:
Given :In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegetables, and 458 reported that they preferred eating vegetables.
To Find :What value of z should be used to calculate a confidence interval with a 95 % confidence level?
Solution:
Confidence level = 95 % i.e.0.95
So, significance level = 5% i.e. 0.05
So, the value of z corresponding to significance level 0.05 should be used to calculate a confidence interval with a 95 % confidence level
So, 
Hence z should be 1.645 to calculate a confidence interval with a 95 % confidence level.