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WITCHER [35]
2 years ago
7

Estimate the value of 50.75 x 0.18 Estimate the value of 196 divided by 0.499

Mathematics
2 answers:
Trava [24]2 years ago
5 0
50.75 × 0.18 = 10.2
196 ÷ 0.499 = 400
DIA [1.3K]2 years ago
3 0
<span>This question is a simple one. To answer this question, you need to understand the description in the question and determine to multiply or divide the number.

The first problem would be:
50.75 x 0.18= 9.135
</span>If you need to estimate, 50.75 is near 50; 0.18 is near 0.2 or 1/5 so it would be: 50/0.2= 10<span>

The second problem would be:
196 / 0.499: 392.785 
If you need to estimate, 0.499 is near 0.5 then 196/0.5 would be 392</span>
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Answer:

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Step-by-step explanation:

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Given two points, we can calculate the slope by dividing the change in y (or the difference in the y-coordinates) by the change in x (or the difference in the x-coordinates). Our two points are (-4, 3) and (2, -6):

m = (3 - (-6)) / (-4 - 2) = 9 / (-6) = -3/2

So, we can update our equation:

y = (-3/2)x + b

The y-intercept is where the graph crosses the y-axis, or the y-value where x = 0. Let's plug in 3 for y and -4 for x:

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Our slope-intercept form is thus:

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2 years ago
2.4 Backgammon. Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two di
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Answer:

The claim is not fair because:

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The <em>probaility</em> of an event is defined as the number of favorable outcomes divided by the number of total possible events.

P (event E) = number of outcomes for event E / number of possible events

1. <u>As </u><u>first step</u><u>, you may draw a table to find the </u><u>sample space</u><u> (set of all possible outcomes)</u>.

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The results of the rolling two dice are summarized in this table:

                    Second roll    1       2       3       4        5      6

First roll

  1                                       (1,1)  (1,2)    (1,3)   (1,4)   (1,5)  (1,6)

  2                                     (2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

  3                                     (3,1)  (3,2)  <u>(3,3)</u>   (3,4)  (3,5)  (3,6)

  4                                     (4,1)   (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

  5                                     (5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

  6                                     (6,1)  (6,2)  (6,3)  (6,4)  (6,5)  <u>(6,6)</u>

<u></u>

2.<u>Now, in that table, you can observe</u>:

The results (3,3) and (6,6) are highlited.

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3) <u>Next, you can calculate the probabilities:</u>

a) Probability rolling two 6s = 1 / 36

b) Probability of rolling two 3s: 1 / 36

4. <u>Conclusion</u>: the probabilities prove that rolling two 6s is just as likely as rolling two 3s.

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