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WITCHER [35]
1 year ago
7

Estimate the value of 50.75 x 0.18 Estimate the value of 196 divided by 0.499

Mathematics
2 answers:
Trava [24]1 year ago
5 0
50.75 × 0.18 = 10.2
196 ÷ 0.499 = 400
DIA [1.3K]1 year ago
3 0
<span>This question is a simple one. To answer this question, you need to understand the description in the question and determine to multiply or divide the number.

The first problem would be:
50.75 x 0.18= 9.135
</span>If you need to estimate, 50.75 is near 50; 0.18 is near 0.2 or 1/5 so it would be: 50/0.2= 10<span>

The second problem would be:
196 / 0.499: 392.785 
If you need to estimate, 0.499 is near 0.5 then 196/0.5 would be 392</span>
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A website reports that 70% of its users are from outside a certain country, and 60% of its users logon the website every day. Su
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Answer:

The value is P (I |  L  )  =     0.63

The probability has increased

Step-by-step explanation:

From the question we are told that

   The percentage that are from outside the country is  P(O) =  0.70

    The  percentage that logs on everyday is  P(L) =  0.60

    The  percentage that logs on everyday that are from the inside the country is     P(L  |  I) =  0.80

Generally using Bayes' Rule the probability that a person is from the country given that he logs on the website every day is mathematically represented as

     P (I |  L  )  =  \frac{P(I)* P(L|I)}{ P(O) *P(L|O) + P(I) *P(L|I) }

Where  P(I) is the percentage that are from inside that country which is mathematically represented as

       P(I) =  1 -  P(O)

      P(I) =  1 -  0.70

      P(I) =  0.30

And P(L| O) is  percentage that logs on everyday that are from the outside  the country which is evaluated as

      P(L| O)  =  1-  P(L| I)

       P(L| O)  =  1-  0.80

       P(L| O)  = 0.20

P (I |  L  )  =  \frac{ 0.3* 0.80 }{ 0.7 *0.20 + 0.3 * 0.8 }    

P (I |  L  )  =     0.63

Given that the percentage that are from inside that country is  P(I) =  0.30

and that the probability that a person is from the country given that he logs on the website every day is  P (I |  L  )  =     0.63

We see that the additional information increased the probability

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1 year ago
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Answer:

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