Answer: Second option, third option and fifth option.
Step-by-step explanation:
In order to solve this exercise it is important to remember the multiplication of signs:
Knowing that, you can distribute the sign and add the like terms. Repeat this procedure in each expression given in the exercise.
Therefore, you get:
You can identify that the expressions ,
and
are equivalent after simplifying.
Answer:
99% Confidence interval: (0.185,0.375)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 150
Number of cars that have faulty catalytic converters, x = 42
99% Confidence interval:
Putting the values, we get:
The 99% confidence interval for the true proportion of new cars with faulty catalytic converters is (0.185,0.375)
Answer:
Joint variation says that:
if and
then the equation is in the form of:
, where, k is the constant of variation.
As per the statement:
If x varies jointly as y and z
then by definition we have;
......[1]
Solve for k;
when x = 8 , y=4 and z=9
then
Substitute these in [1] we have;
⇒
Divide both sides by 36 we have;
Simplify:
⇒
to find z when x = 16 and y = 6
Substitute these value we have;
⇒
Multiply both sides by 9 we have;
Divide both sides by 12 we have;
12 = z
or
z = 12
Therefore, the value of z is, 12
