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Scrat [10]
2 years ago
15

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. x+y = 3, x = 4

−(y−1)^2; about the x-axis.
Mathematics
1 answer:
Ad libitum [116K]2 years ago
4 0
The intersection between the curves are
3, 0
0, 3
The volume of the solids is obtained by
V = ∫ π [ (4 - (y-1)²)² - (3 - y)²] dy with limits from 0 to 3
The volume is
V = 108π/5 or 67.86
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Basing the Results on Probability
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Basing the results on Probability is calculation. The correct option among all the options that are given in the question is the third option or option "c". Probability is basically calculating the chance of an event happening based on an experiment that is performed. I hope the answer comes to your help.
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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
2 years ago
A rectangular football field is 64 meters wide and 100 meters long. A player runs from one corner of the field in a diagonal lin
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Let the distance be d

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The player ran for 119 meters
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2 years ago
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1. An AP Statistics class starts a project to estimate the average number of hours a student at their high school sleeps per nig
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Answer:

Option E

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There are seven boys and five girls in a class. The teacher randomly selects three different students to answer questions. The f
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Which when reduced is:

\frac{7}{66}

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