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Scrat [10]
1 year ago
15

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. x+y = 3, x = 4

−(y−1)^2; about the x-axis.
Mathematics
1 answer:
Ad libitum [116K]1 year ago
4 0
The intersection between the curves are
3, 0
0, 3
The volume of the solids is obtained by
V = ∫ π [ (4 - (y-1)²)² - (3 - y)²] dy with limits from 0 to 3
The volume is
V = 108π/5 or 67.86
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7 0
1 year ago
Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S
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<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}

Substituting values:

V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}

Finally: \\ \\  \boxed{V=\frac{4}{3\left(d-4\right)}}

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