answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vitek1552 [10]
2 years ago
11

Joshua traveled 5 hours from City A to City B. The distance between the cities is 260 miles. First he traveled at the constant s

peed of 40 mi/h, and then at the constant speed of 60 mi/h. How many hours did he travel at the constant speed of 60 mi/h?
Mathematics
1 answer:
ruslelena [56]2 years ago
5 0

Joshua  travelled for 3 hours at the constant speed of 60 mi/h

<h3><u>Solution:</u></h3>

Given that, Joshua traveled 5 hours from City A to City B

The distance between the cities is 260 miles.  

First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.  

So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles

Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles

We have to find how many hours did he travel at the constant speed of 60 mi/h

<em><u>The relation between speed and distance is given as:</u></em>

\text { distance }=\text { speed } \times \text { time. }

\begin{array}{l}{40 \mathrm{mil} / \mathrm{h} \times \mathrm{n} \text { hours }= x \text { miles }} \\\\ {\rightarrow x=40 \mathrm{n} \rightarrow(1)} \\\\ {\text { And } 60 \times(5-\mathrm{n})=260-x \text { miles }}\end{array}

\begin{array}{l}{\rightarrow 300-60 n=260-40 n(\text { from }(1))} \\\\ {\rightarrow 60 n-40 n=300-260} \\\\ {\rightarrow 20 n=40} \\\\ {\rightarrow n=2}\end{array}

So, he travelled 2 hours with speed of 40 mi/h and 5 – 2 = 3 hours with speed of 60 mi/h

Hence, he travelled for 3 hours

You might be interested in
a dance club spent $922 on 40 items.The item include some hats and pairs of shoes.Each hat cost $19 and each pair of shoes cost
Sergio039 [100]

1. H+S=40

2. 19H+25S=922

From 1,

19H+19S=760

Subtract this from 2 to eliminate H,

19H+25S-19H-19S=922-760

6S=162

Solve for S, then use either equation to solve for H.

4 0
2 years ago
A GE lightbulb is supposed to last for 1,200 hours. In fact, light bulbs of this type last only 1,185 hours with a standard devi
dybincka [34]
This can be solved using the formula for t test which is = x - mu over standard deviation divided by the square root of the number of samples. In this case, it is 1185 - 1200 over 70 divided by square root of 100 which give us a value of 2.14 which is equal to .9839 in area. Only rarely, just over one time in a hundred tries of 100 light bulbs, would the average life exceed 1200 hours.
7 0
2 years ago
Rewrite the given expression in the form 3^u where u is a constant or an algebraic expression.
lawyer [7]
Simplifying the given expressions we proceed as follows:
(5sqrt3)^x
=5^x*(3^1/2)^x
=5^x*3^x/2
=5^x3^u
where u=x/2


(1/2)^(x-3)
=1/2^(x-3)
=2^-(3-x)
=2^u
where u=-(3-x)

9/3sqrt(3)
=3/(3)^(1/2)
=3(3)^(-1/2)

16/(3sqrt (2^x))
=1/3*(2^4*2^(-x/2))
=1/3*2^(4-x/2)
=1/3*2^u
where:
u=4-x/2

8 0
2 years ago
Read 2 more answers
An employment agency requires applicants average at least 70% on a battery of four job skills tests. If an applicant scored 70%,
brilliants [131]

Answer:

atleast 52

Step-by-step explanation:

Given that an employment agency requires applicants average at least 70% on a battery of four job skills tests.

An applicant scored 70%, 77%, and 81% on the first three exams,

Since weightages are not given we can assume all exams have equal weights

Let x be the score on the 4th test

Then total of all 4 exams = 70+77+81+x\\= 228+x

Average should exceed 70%

i.e.\bar X \geq 70\\Total\geq 70(4) =280

Comparing the two totals we have

228+x\geq 280\\x\geq 280-228 = 52

Hemust  score on the fourth test a score atleast 52 to maintain a 70% or better average.

3 0
2 years ago
The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t^2 - 0.5t + 3.
Bingel [31]
The average rate of change (m) is the ratio of the change in function value to the width of the interval:
  m = (f(6) - f(2))/(6 - 2)

To compute this, we need to compute f(6) and f(2).
  f(6) = (0.25*6 -0.5)*6 +3.5 = 9.5
  f(2) = (0.25*2 - 0.5)*2 +3.5 = 3.5
Then the average rate of change is
  m = (9.5 - 3.5)/(6 - 2) = 6/4 = 1.5

The average rate of change is 1.5 thousand owners per year.
3 0
2 years ago
Read 2 more answers
Other questions:
  • The after school craft center has 15 boxes of 64 crayons each. In 12 of the boxes , 28 of the crayons have not been used. All th
    10·1 answer
  • Based on the data in this two-way table, if a flower is picked at random, what is the probability that it's a pink rose?
    7·1 answer
  • Isabel's competition, who sells books and no other products, charges a shipping fee of $1.99 per book plus a fixed fee of $3 for
    13·1 answer
  • Lydia spent 4/5 of her money on a mobile phone and 2/3 of the remaining amount on a bag. She had $60 left. How much more money d
    8·1 answer
  • Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in
    14·2 answers
  • A shopper seeking a bargain combined a 25% off coupon and brought enough money to cover 25% of the base price. Why did this shop
    6·1 answer
  • An ant arrives at the snail’s starting position at time minutes and follows the snail’s path. During the interval minutes, the a
    9·1 answer
  • An element with a mass of 100 grams decays by 20.5% per minute. To the nearest minute, how long will it be until there are 10 gr
    9·2 answers
  • Autumn runs a farm stand that sells peaches and grapes. Each pound of peaches sells
    13·1 answer
  • Janie charges $8 an hour to babysit with an additional flat fee of $15 for each babysitting job. She wants to purchase a new gam
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!