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leva [86]
1 year ago
9

A GE lightbulb is supposed to last for 1,200 hours. In fact, light bulbs of this type last only 1,185 hours with a standard devi

ation of 70 hours. What is the probability that a sample of 100 lightbulbs will have an average life of at least 1,200 hours? Mathematics
Mathematics
1 answer:
dybincka [34]1 year ago
7 0
This can be solved using the formula for t test which is = x - mu over standard deviation divided by the square root of the number of samples. In this case, it is 1185 - 1200 over 70 divided by square root of 100 which give us a value of 2.14 which is equal to .9839 in area. Only rarely, just over one time in a hundred tries of 100 light bulbs, would the average life exceed 1200 hours.
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An object is moving at a speed of 850 miles per hour. Express this speed in meters per minute. Round your answer to the nearest
lorasvet [3.4K]

Answer:it would be 1385

Step-by-step explanation:because 850 miles per hour converted into meter per min would be 22799.04 meters per sec and then u would Find the number in the whole number place

4

and look one place to the right for the rounding digit on the right side of the decimal point

7

.Round up if this number is greater than or equal to

5

and round down if it is less than

5

1385

5 0
1 year ago
A quality control technician works in a factory that produces computer monitors. Each day, she randomly selects monitors and tes
jeka94

Answer:

There is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 300

p = 5% = 0.05

Alpha, α = 0.05

Number of dead pixels , x = 24

First, we design the null and the alternate hypothesis  

H_{0}: p = 0.05\\H_A: p > 0.05

This is a one-tailed(right) test.  

Formula:

\hat{p} = \dfrac{x}{n} = \dfrac{24}{300} = 0.08

z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Putting the values, we get,

z = \displaystyle\frac{0.08-0.05}{\sqrt{\frac{0.05(1-0.05)}{300}}} = 2.384

Now, we calculate the p-value from excel.

P-value = 0.00856

Since the p-value is smaller than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

5 0
1 year ago
A formula for 6 gallon of light green paint use 3/8 gallons of white paint. Liam has 9/16 gallon of white paint. Does liam have
FromTheMoon [43]

Answer:

Yes he have enough white paint.

Step-by-step explanation:

We are given

6 gallons of light green paint use → \frac{3}{8} gallons of white paint

using the unitary method

1 gallons of white paint → 6*8/3 gallons of light green paint

                                        → 16 gallons of light green paint

but Liam have 9/16 gallons of white paint

9/16 gallons of white paint → 16* 9/16 gallons of light green paint

                                             → 9 gallons of light green paint

Yes Liam have enough white paint to make 8 gallons of light green paint.  

3 0
1 year ago
A computer store decides to increase the prices of all the items it sells by 15%. The store manager uses matrices to prepare the
Nitella [24]
The manager could perform scalar multiplication on Matrix A, using the scalar 1.15.

Increasing the price by 15% would mean we are taking 100% of the value + another 15%; 100+15 = 115%; 115% = 115/100 = 1.15.

Multiplying every value in Matrix A by 1.15 will give the price raised by 15%.
4 0
2 years ago
Two weeks ago, Alice came home from vacation and noticed that a bean plant was growing in her garden. Today, the stalk is $452$
dimulka [17.4K]
So, on day 1, the plant was say "P" cm tall.

then 2 weeks go by, or 14 days, and the plant grew to 452 cm.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to 452\\
P=\textit{initial amount}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
t=\textit{elapsed time}\to &14\\
\end{cases}
\\\\\\
452=P(1+0.05)^{14}\implies \cfrac{452}{1.05^{14}}=P
7 0
1 year ago
Read 2 more answers
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