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2 years ago

15

The length of a pipe that weighs 45 pounds is cut into 2 pieces. One piece is 3 feet long and weighs 18 pounds. What is the leng

th of the other piece?

1 answer:

muminat2 years ago

6 0

If the length of a uniform pipe is 45 pounds, then the 18 pound piece is 18/45 the length of the pipe. If 18/45 of the length of the pipe is equal to 3 feet, then we can set up the equation:
(18/45)x = 3ft
Where x is the total length of the pipe. Solving for x:
<span>(18/45)x = 3ft
</span>18x = 135
x = 7.5 feet

We now know that the total length of the pipe before being cut is 7.5 feet. Since the first piece was 3 feet, we know that the second piece must be 4.5 feet (7.5 - 3).

Answer: 4.5 feet

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Then, the AVR is:

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Evaluating for x =4:

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Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

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Evaluating for x = 4:

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Then, the AVR is:

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$AVR = \frac{-7}{4+3}$

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Evaluating for x = -1:

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Evaluating for x = 1:

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Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

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Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

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1 year ago

Vladimir79 [104]

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