Bags of sugar from a production line have a mean weight of 5.020 kg with a standard deviation of 0.078 kg. The bags of sugar are
packed in cartons of 20 bags each, and the cartons are piled in lots of 12 onto pallets for shipping. a) What percentage of cartons would be expected to contain less than 100 kg of sugar? b) Find the upper quartile of sugar content of a carton. c) What mean weight of an individual bag of sugar will result in 95% of the pallets weighing more than 1200 kg.?
1 answer:
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Answer:
Step-by-step explanation:
We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.
We know that equation of an object's height t seconds after the launch is in form , where
g = Force of gravity,
= Initial velocity,
= Initial height.
For our given scenario ,
and
. Upon substituting these values in object's height function, we will get:
Therefore, the function for the height of the arrow would be .
The function given is a quadratic function, so the graph will be a parabola. It'll look similar to the photo attached. The minimum cost will be at the vertex of the parabola because that is its lowest point! To find the x-value of the vertex (which is what the question is looking for), use the vertex formula: x = -b/2a. The variable b is the coefficient of the x term in the function, and the variable a is the coefficient of the x² term. In this case, a = 0.125 and b = -5.
x = -(-5)/2(0.125)
x = 5/0.25
x = 20
So, 20 gas grills should be produced each day to maintain minimum costs. Hope that helps! :)
x = -(-5)/2(0.125)
x = 5/0.25
x = 20
So, 20 gas grills should be produced each day to maintain minimum costs. Hope that helps! :)