In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.
In the second case we'd also subtract 1 from both sides, and would obtain
|x-1|>14.
What would the graphs look like?
In the first case, the graph would be on the x-axis with "center" at x=1. From this center count 14 units to the right, and then place a circle around that location (which would be at x=15). Next, count 14 units to the left of this center, and place a circle around that location (which would be -13). Draw a line segment connecting the two circles. Notice that all of the solutions are between -13 and +15, not including these endpoints.
In the second case, x has to be greater than 15 or less than -13. Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right. None of the values in between are solutions.
A=30000+0.03S and B=25000+0.05S.
When A=B, 5000=0.02S, so S=$250000 when the earnings are the same.
The slope of A is smaller than that of B. In excess of this value of S B pays more than A and below it A pays more than B.
So answer option B. (When S=0, clearly A is better than B. Put S=$300000, A pays $39000 and B pays $40000).
The h in p will start the p and the glock I believe
Measure the same distance from the first line to the next at at least three points on the line to get it parallel