answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
julia-pushkina [17]
2 years ago
15

Alex can ski 960 meters in 5 minutes. If his skiing speed is increased by 20 m/min, how many meters can he cover in 10 minutes?

___ m
Mathematics
2 answers:
n200080 [17]2 years ago
6 0
960/50=192

His speed is 192m/min
His speed increases by 20

192+20=212
His skiing speed is 212m/min

To find how many meters he can ski in 10 mins multiply his speed rate by 10
212*10=2120

2120m would be your answer.

I hope this helps :$
pychu [463]2 years ago
3 0
First let's find out how much he can ski per minute without his increase in speed.
To find speed we will have to divide distance by time.
960÷5=232
So his speed is 232 meters per second.
Now to this as add 20.
232+20=252
Then to find out how far he will go in 10 minutes,we will just have to multiply 252 by 10
252×10=2520
So your answer will be that Alex will go 2520 meters in 10 minutes.
You might be interested in
Jon wants to put a circular decorative glass in a table. He cuts a hole in the table that is 20in in diameter. He uses a thin me
Andre45 [30]
To solve for the length of the frame, we are actually solving for the circumference of the circle. Circumference is the measure of the length around edge of the circle. It is given by the formula C=2πr, where r is the radius.

D = 20 in
r = D/2 = 20 in/2 = 10 in
C = 2π(10 in) = 20π in ≈ 62.83 in

The metal frame is about 62.83 inches long. 
8 0
2 years ago
A street lamp casts a shadow 31.5 feet long, while an 8 foot-tall street sign casts a shadow of 14 feet long. What is the length
sergeinik [125]

Answer:

The answer to your question is the height of the lamp is 18.2 ft

Step-by-step explanation:

Data

Street lamp shadow = 31.5 ft

Street sign height = 8 ft

Street sign shadow = 14 ft

Street lamp height = x

Process

1.- To find the height of the lamp use proportions. In this kind of problem, we do not look for the length, but the shadow.

Street lamp height/street lamp shadow = street sign height/street sign

                                                                                                         shadow

Substitution

                                             x / 31.5 = 8 / 14

Solve for x

                                            x = (31.5)(8) / 14

Simplification

                                            x = 254.4 / 14

Result

                                            x = 18.2 ft              

4 0
2 years ago
At the rate of $2.00 per square foot the cost of painting the rectangular board with a semicircular top shown in the figure is $
Elenna [48]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
<span> 
it consists of a rectangle, dimensions  L = 4ft and W = 3ft = Ar = 4ft x 3ft = 12 ft^2

</span>then, you have one half of the area of the circle that has diameter  R = 3ft - radius will be r = 1.5ft the area of that half will be:

Ac = r^2 \pi/ 2
= (1.5 ft)^2 x 3.14 / 2
= 2.25 ft^2 x 3.4/2 
= 7.065 ft^2/ 2 
= 3.5325ft^2

A = Ar + Ac
A = 12ft^2 + 3.5325ft^2
A = 15.5325ft^2

<span>At the rate of $2 per square foot, the cost will be: 
$ 15.5325*2 = 31.07 </span>
5 0
2 years ago
Read 2 more answers
World poultry production was 77.2 million tons in the year 2004 and increasing at a continuous rate of 1.6% per year. Assume tha
dezoksy [38]

Answer:

A) P(t)=77.2\cdot e^{0.016t}

B) 89.157 million tons.

C) In year 2017.

Step-by-step explanation:

We have been given that world poultry production was 77.2 million tons in the year 2004 and increasing at a continuous rate of 1.6% per year.

A). We know that a continuous growth function is in form y=a\cdot e^{kx}, where,

a = Initial value,

k = Growth rate in decimal form.

1.6\%=\frac{1.6}{100}=0.016

Upon substituting our given values, we will get:

P(t)=77.2\cdot e^{0.016t}

Therefore, our required function would be P(t)=77.2\cdot e^{0.016t}, where, P represents world poultry production, in million tons, as a function of the number of years, t, since 2004.

B) To find the world poultry production in the year 2013, we will substitute t=2013-2004=9 in above formula as:

P(9)=77.2\cdot e^{0.016(9)}

P(9)=77.2\cdot e^{0.144}

P(9)=77.2\cdot 1.1548841085249135

P(9)=89.1570531781\approx 89.157

Therefore, the world poultry production in the year 2013 would be 89.157 million tons.

C) To find the number of years it will take for world poultry production to be over 95 million tons, we will equate our function with 95 as:

95=77.2\cdot e^{0.016t}

Divide both sides by 77.2:

1.2305699481865285=e^{0.016t}

Take natural log of both sides:

\text{ln}(1.2305699481865285)=\text{ln}(e^{0.016t})

\text{ln}(1.2305699481865285)=0.016t\text{ln}(e)

0.20747743456981035=0.016t*1

Divide both sides by 0.016:

t=12.9673396606

t\approx 13

Therefore, 13 years after in 2017 world poultry production goes over 95 million tons.

4 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
Other questions:
  • This week luis made 80%of what he made last week. lf he made $72 this week, how much did he make last week
    7·1 answer
  • Gabriela has dinner at a cafe and the cost of her meal is \$45.00$45.00dollar sign, 45, point, 00. Because of the service, she w
    11·2 answers
  • Kyle collects rainwater in two barrels. Last week one barrel collected 1.46 gallons of rainwater. The other barrel collected 0.7
    6·1 answer
  • Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what should the in
    14·2 answers
  • he following data set shows the number of dogs counted in a local park each Saturday for 4 months. 33, 36, 31, 37, 37, 38, 31, 3
    8·2 answers
  • Type the correct answer in the box. Jason builds doghouses for a pet store. Each doghouse is a wooden structure with a rectangul
    14·2 answers
  • Vector A⃗ has magnitude 5.00 and is at an angle of 36.9∘ south of east. Vector B⃗ has magnitude 6.40 and is at an angle of 20.0∘
    5·1 answer
  • A government bureau keeps track of the number of adoptions in each region. The accompanying histograms show the distribution of
    7·1 answer
  • In Speed Study Number 1, we looked at two cars traveling the same distance at different speeds on city streets. Car "A" traveled
    12·1 answer
  • Ted likes to run long distances. He can run 20 \text{ km}20 km20, start text, space, k, m, end text in 959595 minutes. He wants
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!