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oksian1 [2.3K]
2 years ago
12

Calculate the expected gain or loss for Stock ABC. Lose $25 Gain $5 Gain $45 Stock ABC 40% | 15% | 45% Stock JKL| 15% | 65% | 20

% Stock MNO| 5% | 80%| 15%
Mathematics
1 answer:
Rainbow [258]2 years ago
8 0

Answer:

$11

Step-by-step explanation:

\left\begin{array}{c|ccc}&$Lose \$25&$Gain \$5&$Gain \$45\\$Stock ABC&40\%&15\%&45\%\end{array}\right

We want to calculate the expected gain or loss of Stock ABC with the probabilities above.

Note that loss is written in negative.

E$xpected Value =$ (-25  \times 40\%)+(5  \times 15\%) + (45  \times  45\%)\\=(-25 \times 0.4)+(5 \times 0.15)+(45 \times 0.45)\\=-10+0.75+20.25\\=\$11

Stock ABC has an expected gain of $11.

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Michael earns $21 per hour and works 40 hours per week. How many overtime hours would he have to worky in a week for his time-an
Alex73 [517]

Answer:

27 hours

Step-by-step explanation:

The regular hours are paid normally, 21/hr hence working for 40 hours, Michael earns 40*21=$840

To work x hours paid overtime as 1.5 of the normal rate, the rate would be $21*1.5=$31.5/hr

X hours multiplied by rate of $31.5/hr should be at least equal to $840

31.5x>=840

X>=840/31.5>=26.6667 hours and when rounded off

X is 27 hours

6 0
2 years ago
A tiling company completes two jobs. The first job has $1200 in labor expenses for 40 hours worked, while the second job has $15
daser333 [38]

Answer:

The correct option is;

1560 = 30(52) + b

Step-by-step explanation:

The cost of the first job = $1,200 in labor and expenses

The number of hours worked in the first job = 40

The second job costs $1,560 in labor and expenses

The number of hours worked in the second job = 52

If the cost of labor per hour = L and the expenses = b, we have;

$1,200 = 40×L + b......................(1)

$1,560 = 52×L + b.......................(2)

Subtracting equation (1) from (2), we have;

52×L + b - (40×L + b) =  52×L - 40×L + b - b = $1,560 - $1,200 = $360

12×L = $360

L = $360/12 = $30/hour

From equation (1), we have;

$1,200 = 40×L + X =  40×$30 + b

Therefore, the equation that can be used to calculate the y-intercept of the linear equation is either;

1200 = 40(30) + X or 1560 = 32(52) + b, which gives the correct option as 1560 = 32(52) + b

6 0
1 year ago
Find the area of the shaded portion in the equilateral triangle with sides 6. Show all work for full credit. (Hint: Assume that
Vadim26 [7]
So... if you notice the picture below

each circle, has their central angle at the vertex of the triangle
that simply means, 3 circles with a radius of 3, overlapping the triangle

now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors

hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle

so.... the area of those three sectors of 60° each, all three combined, is the same area of half a circle with a radius of 3

so    \bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\textit{length of one side}\\\\
-----------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad r=radius\\\\
\textit{area of half a circle}\\\\
A=\cfrac{\pi r^2}{2}\\\\
-----------------------------\\\\

\bf \textit{now, let us use the side of 6, and radius of 3}
\\\\\\

\begin{array}{clclll}
\cfrac{6^2\sqrt{3}}{4}&-&\cfrac{\pi 3^2}{2}\\
\uparrow &&\uparrow \\
triangle's&&semi-circle's
\end{array}\impliedby \textit{area of shaded area}\\\\
-----------------------------\\\\
\boxed{\cfrac{36\sqrt{3}}{4}-\cfrac{9\pi }{2}}

you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format

8 0
2 years ago
Read 2 more answers
Solve the given initial value problem and determine how the interval in which the solution exists depends on the initial value y
zalisa [80]

Answer:

y has a finite solution for any value y_0 ≠ 0.

Step-by-step explanation:

Given the differential equation

y' + y³ = 0

We can rewrite this as

dy/dx + y³ = 0

Multiplying through by dx

dy + y³dx = 0

Divide through by y³, we have

dy/y³ + dx = 0

dy/y³ = -dx

Integrating both sides

-1/(2y²) = - x + c

Multiplying through by -1, we have

1/(2y²) = x + C (Where C = -c)

Applying the initial condition y(0) = y_0, put x = 0, and y = y_0

1/(2y_0²) = 0 + C

C = 1/(2y_0²)

So

1/(2y²) = x + 1/(2y_0²)

2y² = 1/[x + 1/(2y_0²)]

y² = 1/[2x + 1/(y_0²)]

y = 1/[2x + 1/(y_0²)]½

This is the required solution to the initial value problem.

The interval of the solution depends on the value of y_0. There are infinitely many solutions for y_0 assumes a real number.

For y_0 = 0, the solution has an expression 1/0, which makes the solution infinite.

With this, y has a finite solution for any value y_0 ≠ 0.

8 0
2 years ago
"A consultant compiled the following data set that shows" the number of visits made to the National Museum of American History f
aalyn [17]

Answer:

Step-by-step explanation:

The best option is for the consultant to remove these data points because they are outliers.  Unusual data points which are located far from rest of the data points are known as outliers.

3 0
2 years ago
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