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2 years ago

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Calculate the expected gain or loss for Stock ABC. Lose $25 Gain $5 Gain $45 Stock ABC 40% | 15% | 45% Stock JKL| 15% | 65% | 20

% Stock MNO| 5% | 80%| 15%

1 answer:

Rainbow [258]2 years ago

8 0

Answer:

$11

Step-by-step explanation:

$\left\begin{array}{c|ccc}&$Lose \$25&$Gain \$5&$Gain \$45\\$Stock ABC&40\%&15\%&45\%\end{array}\right$

We want to calculate the expected gain or loss of Stock ABC with the probabilities above.

Note that loss is written in negative.

$E$xpected Value =$ (-25 \times 40\%)+(5 \times 15\%) + (45 \times 45\%)\\=(-25 \times 0.4)+(5 \times 0.15)+(45 \times 0.45)\\=-10+0.75+20.25\\=\$11$

Stock ABC has an expected gain of $11.

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Mr. James has cylindrical beakers that measure 4 inches in diameter and are 9 inches high. What is the volume contained within t

kirill115 [55]

The equation to find the volume of a cylinder is V = pi•r^2•h.
The radius is half of the diameter. Since Mr. James' beakers have a diameter of 4, their radius would be 2. 2 squared is 4.
Their height is 9 inches.
V = 3.14•4•9
V = 3.14•36
V = 113.04
The answer is C, or 113.04 cubic inches.

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2 years ago

Read 2 more answers

Eudora ran from her home to her secret laboratory at an average speed of 12\text{ km/h}12 km/h12, start text, space, k, m, slash

OleMash [197]

Answer:

Eudora spent 0.5 hours from home to library and 1.5 hours from library to school

Step-by-step explanation:

Given

Home to Library:

$S_1 = 12km/h$ -- Average Speed

Library to School

$S_2 = 76km/h$ -- Average Speed

Total

$Distance = 120km$

$Time = 2\ hr$

Required

Determine the time taken from home to library and from library to school

Let the time spent from home to library be x. So, from library to school will be: 2 - x

So, we have:

Home to Library:

$S_1 = 12km/h$ -- Average Speed

$T_1 =x$ -- Time

Library to School

$S_2 = 76km/h$ -- Average Speed

$T_2 =2 - x$ -- Time

Distance is calculated as:

$Distance = Speed * Time$

Home to Library:

$D_1 = S_1 * T_1$

$D_1 = 12 * x$

$D_1 = 12x$

Library to School:

$D_2 = S_2 * T_2$

$D_2 = 76 * (2- x)$

$D_2 = 152- 76x$

The total distance is 120km. So, we have:

$120km = D_1 + D_2$

$120 = 12x + 152 - 76x$

Collect Like Terms

$120 - 152 = 12x - 76x$

$-32 = -64x$

$-64x=-32$

Solve for x

$x = \frac{-32}{-64}$

$x = 0.5$

Recall that:

$T_1 =x$

$T_2 = 2 - x$

So, we have:

$T_1 = 0.5$

$T_2 = 2 -0.5 = 1.5$

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2 years ago

How many pounds of water must be evaporated from 50 pounds of a 3% salt solution so that the the remaining solution will be 5 %

svlad2 [7]

Answer:

Step-by-step explanation:

This is kinda tricky, but not nearly as bad as d = rt problems. Those are a nightmare!

We will make a table for this:

#lbs solution * % salt = lbs. salt

3% solution

- <u>Water </u>

New solution

And we will now fill in what we know. The 3% solution part is easy. The number of pounds of that is 50 and the percent salt in 3% salt is....well, 3%. As a decimal, it is .03:

#lbs solution * %salt = lbs salt

3% solution 50 * .03 = 1.5

- <u>Water </u>

New solution

The last column there with a 1.5 in it is the product of 50 times .03, since that is what the formula at the top of the table tells us we have to use. Now for the water. That's easy, too, since the amount of water we are evaporating (notice the subtraction sign out front of the word "water"; that indicates we are removing water) is our unknown, and we also know that water has 0% salt in it:

#lbs solution * %salt = lbs. salt

3% solution 50 * .03 = 1.5

- <u>Water x * 0 = 0 </u>

New solution

Now all we have left is the new solution row and the equation. Finding the equation from a mixture table is as easy as it can be! Super easy!

The new solution will be 50 - x since, going down column 1, we are subtracting the water from the 3% solution, the % salt is to be 5%:

#lbs. solution * %salt = lbs. salt

3% solution 50 * .03 = 1.5

- <u>Water x * 0 = 0 </u>

New solution 50 - x * .05 = 2.5 - .05x

Now we're ready for our equation. I got the 2.5 - .05x from multiplying

.05(50 - x), just so you know.

if we had to subtract the water from the salt solution and set it equal to the new solution in the first column, we also have to do it in the third column:

1.5 - 0 = 2.5 - .05x and solve for x:

-1 = -.05x so

x = 20 pounds of water

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2 years ago

Evaluate. 58−(14)2=58-142= ________

nasty-shy [4]

For this case we have the following expression:

$58- (14) ^ 2$

The first step is to solve the quadratic term.

We have then:

$58- (14) ^ 2 = 58-196$

Then, the second step is to subtract both resulting numbers:

$58- (14) ^ 2 = -138$

We observe that the result obtained is a negative number.

Answer:

The result of the expression is given by:

$58- (14) ^ 2 = -138$

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2 years ago

FreezeFrame, a social networking site, sent out a survey in which the users simply click a response to join the sample. One of t

kramer

Answer:

Here, Convenience sampling is used by the poll

Explanation:

Convenience sampling also called as opportunity, grab or accidental sampling is a kind of non-likelihood testing that includes the sample being drawn from that piece of the populace that is near hand. This sort of sampling is most valuable for pilot testing.

Convenience sampling is a procedure used to make sample according to straightforward entry, readiness to be a sample's part , accessibility at a given scheduled slot.

So, this method of sampling is biased and don't results in desired outcomes.

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2 years ago