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Keith_Richards [23]
2 years ago
7

You put $1200 in an account that earns 3% simple interest. Y= a (1 + r)t Find the total amount in the account after four years.

Mathematics
1 answer:
olchik [2.2K]2 years ago
6 0

Hello!

To find how much money total will be in the account after four years, you need to use the function, y = a(1 + r)^{t}, as seen above. In this function, a is the starting value, r is the interest rate, and t is the amount of time (in years).

Before substituting values into the function, we need to convert 3% into a decimal. Remember that all percentages are out of 100, so we divide 3 by 100 and remove the percentage sign, or move the decimal two places to the left.

3/100 = 0.03 | 0.03 is the interest rate.

With all the necessary values, we can find the total amount in the account. In this case, a = 1200, r = 0.03, and t = 4.

y = 1200(1 + 0.03)^{4}

y = 1200(1.03)^{4}

y = 1200(1.12550881)

y = 1350.610572, which can be rounded to 1350.61 dollars.

Therefore, after 4 years, the total amount in the account will be about 1350.61 dollars.

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The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
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Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

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The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
1 year ago
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