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1 year ago

How many unit angles does the smaller angle of a tan pattern block turn through?

Mathematics

2 answers:

Anna71 [15]1 year ago

8 0

So you multipliy 9 times 4 and that's 36

galina1969 [7]1 year ago

4 0

Ok so all you have to do is multiple 9 And 4 ok then you will get you answer

Hope this helps

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A certain type of plywood consists of six layers. The thickness of the layers are independent and normally distributed with mean

Ira Lisetskai [31]

Answer:

a.) The mean of the six layered plywood is 30 mm

The standard deviation is 0.49 mm

b.) That the thickness is less than 28 mm has a probability of 0.000022.

Step-by-step explanation:

There are six layers in a plywood that is considered. It is also given that the layers are independent and normally distributed.

The thickness of the layers of the plywood have a mean, $\mu$ = 5 mm

and a standard deviation, $\sigma$ = 0.2 mm.

a.) Therefore the mean of the six layered plywood is = 6 $\mu$

= 6 × 5 mmm

= 30 mm

The standard deviation of the six layered plywood = $\sqrt{6 \sigma^{2} }$ = $\sqrt{6 \times (0.2)^2}$ = 0.49 mm

b.) We are given to find that the probability of the plywood is less than 28 mm thick.

P( thickness < 28 mm)

P( Z < $\frac{(28 - 30)}{0.49}$ ) = P(Z < $(\frac{-2}{0.49} )$ ) ⇒ P( Z < -4.082) = 0.000022

8 0

1 year ago

Caroline bought 20 shares of stock at 10 ½, and after 10 months the value of the stocks was 11 ¼. If Caroline were to sell all h

OleMash [197]

20 shares at 10 1/2 (or 10.5) = 20 * 10.5 = 210
20 shares at 11 1/4 (or 11.25) = 20 * 11.25 = 225

so the profit made would be : 225 - 210 = $ 15 <==

4 0

1 year ago

A new curing process developed for a certain type of cement results in a mean compressive strength of 5000 kilograms per square

Sedbober [7]

Answer:

$\alpha =0.0668$

Step-by-step explanation:

Data given and notation

The info given by the problem is:

$n=25$ the random sample taken

$\mu =5000$ represent the population mean

$\sigma =100$ represent the population standard deviation

The critical region on this case is $\bar X$ so then if the value of $\bar X \geq 4970$ we fail to reject the null hypothesis. In other case we reject the null hypothesis

Null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the true mean is 5000, the system of hypothesis would be:

Null hypothesis: $\mu = 5000$

Alternative hypothesis: $\mu \neq 5000$

Let's define the random variable X ="The compressive strength".

We know from the Central Limit Theorem that the distribution for the sample mean is given by:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

Find the probability of committing a type I error when H0 is true.

The definition for type of error I is reject the null hypothesis when actually is true, and is defined as $\alpha$ the significance level.

So we can define $\alpha$ like this:

$\alpha= P(Error I)= P(\bar X$

And in order to find this probability we can use the Z score given by this formula:

$Z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And the value for the probability of error I is givn by:

$\alpha= P(\bar X$

4 0

1 year ago

A yard is equal in length to three feet. The function f(x) takes a measurement in yards (as input) and returns a measurement in

Grace [21]

If it takes yards and turns it into feet then it just multiplies it by 3

so if the input is 10.5 then you just multiply it by three

31.5 feet is the imput

3 0

1 year ago

Read 2 more answers

What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?

Darya [45]

Answer:

$4 \sqrt{2} i$