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gulaghasi [49]
2 years ago
11

How many positive integers smaller than $1{,}000{,}000$ are powers of $2$, but are not powers of $8$? you may find it useful to

consider that $2^{10}=1024$?
Mathematics
2 answers:
Fudgin [204]2 years ago
7 0

Answer:

13!!!!!!!!!

kolbaska11 [484]2 years ago
5 0
2^19 is the highest you can go lower than 1,000,000.

8^6 is the highest you can go lower than 1,000,000

just Subtract the Exponents.
19-6=13

2^13 so there are 13 integers that are the power of 2 but not the power of 8 and less than 1,000,000.
You might be interested in
A law firm is going to designate associates and partners to a big new case. The daily rate charged to the client for each associ
Vikentia [17]

Answer:

Associates=7

Partners=10

Step-by-step explanation:

Let the number of associates be x while partners be y. Since they are a total of 17 then

x+y=17

Therefore, x=17-y

Also considering the charges then

800x+1800y=23600

Subsituting x with 17-y then

800(17-y)+1800y=23600

13600-800y+1800y=23600

1000y=10000

Y=10

X=17-y=17-10=7

4 0
2 years ago
If a hospital patient is given 100 milligrams of medicine, which leaves the bloodstream at 14% per hour, how many milligrams of
sergejj [24]

Answer:

<em>24.66 mg</em><em> of medicine will be left.</em>

Step-by-step explanation:

The given exponential equation is,

A(t)=ie^{rt}

Where,

A(t) = amount after time t

i = initial amount = 100 mg

r = rate of change = -14% = -0.14 (-ve is taken because the amount is decreasing)

t = time = 10 hours

Putting the values,

A(t)=100e^{-0.14\times 10}

=100e^{-1.4}

=24.66\ mg

3 0
2 years ago
(a) Find a vector-parametric equation r⃗ 1(t)=⟨x(t),y(t),z(t)⟩r→1(t)=⟨x(t),y(t),z(t)⟩ for the shadow of the circular cylinder x2
motikmotik

Answer: (a) r1(t) = <2cost , 0 , 2sint>

(b) <2cost , (1 - 12sint - 10cost)/8 , 2sint>

Step-by-step explanation:

x2+z2=4

a)

Now, in the xz plane, we know that y = 0...

So, x^2 + z^2 = 4 will simply be a circle centered at (0,0)..

This can be easily parameterized as

x = 2cos(t)

z = 2sin(t)

So, the required parameterization is :

r1(t) = <2cost , 0 , 2sint>

b)

Cylinder : x^2 + z^2 = 4

Plane : 5x+8y+6z=1

Easily enough, the x^2 + z^2 = 4 can again be parameterized as

x = 2cost , z = 2sint

With this, we can find y using plane equation...

5x+8y+6z=1

5(2cost) + 8y + 6(2sint) = 1

8y = 1 - 12sint - 10cost

y = (1 - 12sint - 10cost)/8

So, the parameterization is :

<2cost , (1 - 12sint - 10cost)/8 , 2sint>

6 0
2 years ago
O is the centre of the circle, EF is a tangent, angle BCE=28 degrees, angle ACD=31 degrees.
Yuki888 [10]

Answer:

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

a. because angle between tangent and chord is equal to the angle(s) in alternate segment.

b. because angles in triangles add up to 180˚, 180-28=152 and because isosceles triangle, 152/2=76˚

c. because angles in triangles add up to 180˚ and opposite angles in a cyclic quadrilateral add up to 180˚, 31+76=107, 180-107=73, 73-28=45, angles in triangle so 180-(31+45)=104˚

d. 28*2=56˚ because angles at circumference are half angles at centre

4 0
2 years ago
The product of two rational numbers is -28/75. If one of the numbers is 14/25, find the other
Law Incorporation [45]

Answer:

-3/2

Step-by-step explanation:

Let x be the missing number

  • x*\frac{14}{25} = \frac{-28}{75}
  • x = \frac{-28}{75} * \frac{25}{14}          inverse 14/25 since it's a fraction
  • x = \frac{-28*25}{75*14}
  • x = \frac{-4*7*25}{25*3*7*2}          write 75 as 25*3 and -28 as -4*7 to simplify
  • x = \frac{-4}{6}            -4 is left on the top and 6 = 3*2
  • x = \frac{-3*2}{2*2}
  • x=   \frac{-3}{2}      
8 0
2 years ago
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