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2 years ago

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After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an

d an increase of 8% per year, the population is 34,560. Which equation can be used to predict, y, the number of people living in the town after x years? (Round population values to the nearest whole number.)
y = 32,000(1.08)x
y = 32,000(0.08)x
y = 34,560(1.08)x
y = 34,560(0.08)x

2 answers:

galben [10]2 years ago

4 0

Answer:

$y=32000(1+0.08)^x$

Step-by-step explanation:

Exponential growth function is $y=a(1+r)^x$

Where 'a' is the initial population

r is the rate of growth and x is the time period in years

a steady population of 32,000. So initial population is 32,000

an increase of 8% per year. the rate of increase is 8% that is 0.08

a= 32000 and r= 0.08

Plug in all the values in the general equation

$y=a(1+r)^x$

$y=32000(1+0.08)^x$

$y=32000(1+0.08)^x$

dezoksy [38]2 years ago

4 0

y=32,000(1.08)x

32,00 Starting point

1.08 Growth which is 8 percent and the original value

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