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2 years ago

How to do it and how to work it out and stuff

Mathematics

1 answer:

gogolik [260]2 years ago

8 0

Oof I had that question and I was so stuck on it I still dont know it till this day ah life is hard

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TWENTY POINTS!!! Baxter is thinking about buying a car for $18,500. The table below shows the projected value of two different c

Anika [276]

Part A: Linear function

explanation:
The table for the value of the two cars with time are given as follows;
Years Car 1 Car 2
1 18,500 18,500
2 17,390 17,500
3 16,500 16,346.6
Plotting the give data, we have;
From the plot of the data, the function that can be used to describe the values of both cars after a fixed number of years is a linear function

Hope this helps a bit

7 0

2 years ago

Read 2 more answers

The table shows the number of condo sales per month for a new condo building.

Tresset [83]

Answer:

Do you happen to have the graph or anything to add to it? Because it is kind of difficult to see when it looks like that. I think it would be 11, 8, 5, and

y-2--3(x-3)

y+ 11 = 31-0)

y+ 1 =-3(x-2)

Y-1--31% +8)

y-11 =-3lx -0)

8 0

2 years ago

A uniform bar of length l and weight w is attached to a wall with a hinge that exerts a horizontal force hx and a vertical force

maria [59]

The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0

4 0

2 years ago

The steps to derive the quadratic formula are shown below: Step 1 ax2 + bx + c = 0 Step 2 ax2 + bx = − c Step 3 x2 + b over a ti

Nostrana [21]

Answer:

$x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1:

$ax^2+bx+c = 0$

Step 2:

$ax^2+bx = -c$

Step 3:

$\frac{ax^2+bx}{a} = \frac{-c}{a}$

Step 4:

Adding $\frac{b^2}{4a^2}$ to both sides to complete the square

$x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-c}{a} + \frac{b^2}{4a^2}$

Step 5:

$x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-4ac+b^2}{4a^2}$

Step 6:

Taking square root on both sides

$x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}$

3 0

1 year ago

5r^2-44r+120 = -30r+11r

garik1379 [7]

$5r^2-44r+120 = -30r+11r \\ \\ 5f^2 - 44r + 120 = -19r \\ \\ 5r^2 - 44r + 120 + 19r = 0 \\ \\ 5r^2 - 25r + 120 = 0 \\ \\ r = \frac{25+5 \sqrt{71i} }{10} , \frac{25-5 \sqrt{71i} }{10} \\ \\ r = \frac{5+ \sqrt{71i} }{2} , \frac{5 - \sqrt{71i} }{2} \\ \\ ANSWER: r = \frac{5+ \sqrt{71i} }{2} , \frac{5 - \sqrt{71i} }{2}$

3 0

1 year ago