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2 years ago

The ratio of the lengths of corresponding parts in two similar solids is 5:1,

2 answers:

7 0

The ratio of the surface areas of two similar solids can be computed by squaring the given ratio of the corresponding sides. For this given,
r = (5:1)^1
r = 25:1

Thus, the ratio of the surface areas of the similar solids is 25:1.

Natali5045456 [20]2 years ago

5 0

25:1 on apex

Step-by-step explanation:

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Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in

Sever21 [200]

Given the heights, radii, and diagonals of the vertical cross-sections of the models, the model in which the lateral surface meet the base at a right angle is the model in which the height, the diameter and the diagonal of the vertical cross-section forms a right triangle.

i.e. the sum of the squares of the height (h) and the diameter (d) gives the square of the diagonal vertical cross-section (l).

For model 1:

radius: 14 cm, thus diameter = 2(14) = 28 cm
height: 48 cm
diagonal: 50 cm

 $d^2+h^2=28^2+48^2 \\ \\ =784+2,304=3,090\neq50^2=l^2$

Thus, the lateral surface of model 1 does not meets the base at right angle.

For model 2:

radius: 6 cm, thus diameter = 2(6) = 12 cm
height: 35 cm
diagonal: 37 cm

[tex]d^2+h^2=12^2+35^2 \\ \\ =144+1,225=1,369=37^2=l^2[/tex]

Thus, the lateral surface of model 2 meets the base at right angle.

For model 3:

radius: 20 cm, thus, diameter = 2(20) = 40 cm
height: 40 cm
diagonal: 60 cm

 $d^2+h^2=40^2+40^2 \\ \\ =1,600+1,600=3,200\neq60^2=l^2$

Thus, the lateral surface of model 3 does not meets the base at right angle.

For model 4:

radius: 24 cm, thus, diameter = 2(24) = 48 cm
height: 9 cm
diagonal: 30 cm

 $d^2+h^2=48^2+9^2 \\ \\ =2,304+81=2,385\neq30^2=l^2$

Thus, the lateral surface of model 3 does not meets the base at right angle.

Therefore, the model in which the lateral surface meets the base at a right angle is model 2 (option b)

8 0

2 years ago

Read 2 more answers

Prove that. 1-sin2A=2sin^2(45-A)

Liula [17]

Answer:

Proved

Step-by-step explanation:

2 sin square( 45°-A)

(therefore;

by trigonometry ratios

sin45°=1)

=2sin2(1-A)

=2sin(1-A)

=1+sin2A

hence proved

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Tysm

6 0

2 years ago

Divide $3,300 into three parts whose ratio is 1:3:7.

AveGali [126]

1+3+7=11

The first part is
3,300×(1÷11)
=300
The second part is
3,300×(3÷11)
=900
the third part is
3,300×(7÷11)
=2,100

8 0

2 years ago

-3(2t - 1) = t + t + t + 3

Allisa [31]

T = 0

isolate the variable

4 0

2 years ago

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Find all of the polar coordinates of point P if p=(1,-pi/6)

Mama L [17]

Answer:

The all polar coordinates of point P are (1 , -pi/6 + 2nn) and (-1, -pi/6+(2n+1)n).

Step-by-step explanation:

The polar coordinates can be written as (r,Ф)= (r,Ф+2nn) or (r,Ф) =(-r,Ф+(2n+1)n) and n is any integer value.

We are given p=(1,-pi/6)

P(r,Ф), then r = 1 and Ф = -pi/6

The polar coordinates will be

P(r,Ф)= (r,Ф+2nn) = (1 , -pi/6 + 2nn) and n is any positive integer and the value of r is positive.

P(r,Ф) =(-r,Ф+(2n+1)n) = (-1, -pi/6+(2n+1)n) and n is any positive integer and the value of r is negative.

The all polar coordinates of point P are (1 , -pi/6 + 2nn) and (-1, -pi/6+(2n+1)n)

6 0

2 years ago

Read 2 more answers