Kevin, because the problem says the difference of a number (x) and 20, and since 20 is mentioned second, it would therefore be the second number in the problem
Complex solutions, namely roots with a √(-1) or "i" in it, never come all by their lonesome, because an EVEN root like the square root, can have two roots that will yield the same radicand.
a good example for that will be √(4), well, (2)(2) is 4, so 2 is a root, but (-2)(-2) is also 4, therefore -2 is also a root, so you'd always get a pair of valid roots from an even root, like 2 or 4 or 6 and so on.
therefore, complex solutions or roots are never by their lonesome, their sister the conjugate is always with them, so if there's a root a + bi, her sister a - bi is also coming along too.
if complex solutions come in pairs, well, clearly a cubic equation can't yield 3 only.
Answer:
69
Step-by-step explanation:
Square root of 1300= 36
(37)²>1300>(36)²
Therefore , the requirement no. to be added to get a perfect square
=(37)²=1369
= 1369- 1300=69
The least no. Of sapling he needs for this = 69
