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just olya [345]
2 years ago
13

A rectangular floor tile is shown it dimensions are given to the nearest 0.1 metres the tile is only able to sustain maximum pre

ssure of 200 newtons per square metre correct to the nearest 5N/m² given that pressure=Force
area
Work out the maximum force in newtons that can safely be applied to the tile
Mathematics
1 answer:
egoroff_w [7]2 years ago
4 0

Answer:

736 N

Step-by-step explanation:

The dimensions of the rectangular tile are:

Length = 2.3m

Width = 1.6m

The pressure exerted on a surface is given by the formula

p=\frac{F}{A}

where

p is the pressure

F is the force exerted

A is the area on which the force is exerted

In this problem, we have:

p=200 N/m^2 is the maximum pressure that the tile is able to sustain

A is the area of the tile, which can be calculated as the product between length and width, so:

A=L\cdot w =(2.3)(1.6)=3.68 m^2

Re-arranging the formula for F, we can find the maximum force that can be safely applied to the tile:

F=pA=(200)(3.68)=736 N

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From the question we are told that

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