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marishachu [46]

2 years ago

12

A training field is formed by joining a rectangle and two semicircles, as shown below. the rectangle is 93m long and 64m wide. f

ind the area of the training field. use the value 3.14 for ? , and do not round your answer. be sure to include the correct unit in your answer.

1 answer:

raketka [301]2 years ago

4 0

If the field is 68 m wide, then each semicircle has a diameter of 68 m ,

or a radius of 68/2 = 34 m.

Area of two semicircles = Pi*R^2 = Pi(34)^2 = 3629.84 m^2

Area of Rectangle = LW = (95)(68) = 6460 m^2 Total Area = 6460 + 3629.84 = 10089.84 m^2

You might be interested in

HURRY! Which table represents a linear function?

jeka94

Remember that to tell if a function is linear for a table, you should look for a constant rate of change, and the only function that has a constant rate of change is the first one. $x$ is increasing by 1, and $y$ is increasing by 0.5.

Now that we know that, lets find the equation of our table.
First, lets take tow points from our table: (1, $\frac{1}{2}$ ) and $(2,1)$ .
Next, use the slope formula: $m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} }$
We know for our points that $y_{2}=1$ , $y_{1}= \frac{1}{2}$ , $x_{2}=2$ , and $x_{1}=1$ , so lets replace those point in our formula to find $m$ :
$m= \frac{1- \frac{1}{2} }{2-1}$
$m= \frac{1}{2}$

Finally, we can use the point slope formula $y-y_{1}=m(x-x_{1})$ to find our equation:
$y- \frac{1}{2} = \frac{1}{2} (x-1)$
$y- \frac{1}{2} = \frac{1}{2} x- \frac{1}{2}$
$y= \frac{1}{2}x$

We can conclude that the first table represents a linear function, and its equation is $y= \frac{1}{2}x$

7 0

2 years ago

One column of numbers consists of 61, 24, and 47. When the digits of the numbers are added together, the result is 6 + 1 + 2 + 4

ololo11 [35]

The question is incomplete because it must content a list of choices to select the right one.

Any way, a conclusion that you can make, and that is a common one for this kind of questions, is about whether the sum of the numbers of the second column may or not be the same sum of the numbers of the first column.

The condition for the two sums be the same is that when the digits of the second column are added together the result be the same obtained for the sum of the digits of the first column. In this case that is 6.

So, the possible answer is:

<span>If the end result from the second column is not 6, then the sum of the numbers in the first column is not equal to the sum of the numbers in the second column.</span>

5 0

2 years ago

Read 2 more answers

Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining wh

snow_tiger [21]

Answer:

Step-by-step explanation:

Corresponding fuel efficiencies of manufacturer A's car and manufacturer B's car form matched pairs.

The data for the test are the differences between the efficiencies of manufacturer A's car and manufacturer B's car

μd = fuel efficiency of manufacturer A's car minus the fuel efficiency of manufacturer B's car.

A B diff

32 28 4

27 22 5

26 27 - 1

26 24 2

25 24 1

29 25 4

31 28 3

25 27 - 2

Sample mean, xd

= (4 + 5 - 1 + 2 + 1 + 4 + 3 - 2)/8 = 2

xd = 2

Standard deviation = √(summation(x - mean)²/n

n = 8

Summation(x - mean)² = (4 - 2)^2 + (5 - 2)^2 + (- 1 - 2)^2 + (2 - 2)^2 + (1 - 2)^2 + (4 - 2)^2 + (3 - 2)^2 + (- 2 - 2)^2 = 44

Standard deviation = √(44/8

sd = 2.35

For the null hypothesis

H0: μd = 0

For the alternative hypothesis

H1: μd ≠ 0

This is a two tailed test and the distribution is a students t. Therefore, degree of freedom, df = n - 1 = 8 - 1 = 7

2) The formula for determining the test statistic is

t = (xd - μd)/(sd/√n)

t = (2 - 0)/(2.35/√8)

t = 2.41

We would determine the probability value by using the t test calculator.

p = 0.047

Since alpha, 0.1 > the p value 0.047, then we would reject the null hypothesis. Therefore, at 1% significance level, we can conclude that there is a significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

6 0

2 years ago

The 8th term of a GP is -7/32 find its common ratio if its first term is 28

Ugo [173]

<h2>Common ratio = -1/2</h2>

Step-by-step explanation:

$\text{8}^{th}$ term of a Geometric progression is given as $\dfrac{-7}{32}$ . The first term is given as $28$ .

Any general Geometric progression can be represented using the series $a,ar,ar^{2},ar^{3},ar^{4}...\text{ }ar^{n-1}$ .

The first term in such a GP is given by $a$ , common ratio by $r$ , and the $n^{th}$ term is given by $ar^{n-1}$ .

In the given GP, $a=28;t_{8}=ar^{7}=\dfrac{-7}{32}\\\\28r^{7}=\dfrac{-7}{32}\\\\r^{7}=\dfrac{-1}{128}\\\\r=\dfrac{-1}{2}$

∴ Common ratio is $\dfrac{-1}{2}$ .

5 0

2 years ago

Alicia drove 265 miles in 5 hours. What is the average rate that she traveled?

Bumek [7]

265/5 = 53/1

53 miles per hour.

*I hope this helped!

5 0

2 years ago

Read 2 more answers