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marishachu [46]
1 year ago
12

A training field is formed by joining a rectangle and two semicircles, as shown below. the rectangle is 93m long and 64m wide. f

ind the area of the training field. use the value 3.14 for ? , and do not round your answer. be sure to include the correct unit in your answer.
Mathematics
1 answer:
raketka [301]1 year ago
4 0
If the field is 68 m wide, then each semicircle has a diameter of 68 m ,

or a radius of 68/2 = 34 m.

Area of two semicircles = Pi*R^2 = Pi(34)^2 = 3629.84 m^2
 
Area of Rectangle = LW = (95)(68) = 6460 m^2 Total Area = 6460 + 3629.84 = 10089.84 m^2
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If two different people are randomly selected from the 884 subjects, find the probability that they are both women. Round to fou
galina1969 [7]
The answer is 0.3274 
5 0
1 year ago
Given right triangle ABC which of the following statements must be true? Check all that apply.
Pachacha [2.7K]

Answer:

Option A. <A and <B are complementary angles

Option D. Sin(C)=Cos(90\°-C)

Step-by-step explanation:

we know that

If ABC is a right triangle

then

------> by complementary angles

and

Sin(C)=Cos(A)

Cos(C)=Sin(A)

Remember that

A=90\°-C

so

Sin(C)=Cos(90\°-C)

Cos(C)=Sin(90\°-C)

5 0
2 years ago
A driver brings a car to a full stop in 2.0s. It’s acceleration is -11 m/s^2. How far did the car travel while braking
tensa zangetsu [6.8K]

Answer:

  22 m

Step-by-step explanation:

The distance traveled is ...

  d = (1/2)at^2

where "a" is the magnitude of the acceleration.

  d = (1/2)(11 m/s^2)(2 s)^2

  d = 22 m

The car traveled 22 meters while braking.

6 0
1 year ago
Read 2 more answers
The table below shows the functions to represent the sale f(t), in thousands, of four companies in t years.
Tcecarenko [31]
Hi there

the companies showed an exponential growth in sale are

Company C with
f(t) = 1.26t

Company D with
f(t) = 1.09t

Because
1+r where r is the rate of growth

the rate of growth of Company c is 1+26%

The rate of growth of company D is
1+9%


So it's option d

Good luck!
4 0
2 years ago
PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab
Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

m=\frac{y_2-y_1}{x_2-x_1}

The product of slopes of two perpendicular lines is -1.

Slope of GR is

\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}

Slope of RT is

\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1

Product of slopes of GR and RT is

\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

(x,y)\rightarrow(x-1,y-2)

Then the coordinates of T' are

(2,6)\rightarrow(2-1,6-2)

(2,6)\rightarrow(1,4)

Slope of RT' is

\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}

Product of slopes of GR and RT' is

\frac{-4}{3}\times \frac{3}{4}=-1

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0
1 year ago
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