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harina [27]
2 years ago
8

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ian. Further, 103 have taken courses in both Spanish and French, 23 have taken courses in both Spanish and Russian, and 14 have taken courses in both French and Russian. If 2 092 students have taken at least one of Spanish, French, and Russian, how many students have taken a course in all three languages

Mathematics
1 answer:
ElenaW [278]2 years ago
3 0

Answer:

n(S\cap F \cap R)=7

Step-by-step explanation:

The Universal Set, n(U)=2092

n(S)=1232\\n(F)=879\\n(R)=114

n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14

Let the number who take all three subjects, n(S\cap F \cap R)=x

Note that in the Venn Diagram, we have subtracted n(S\cap F \cap R)=x from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, n(S\cap F \cap R)=7

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Answer:

The probability of you winning is 1/3

No, it is not a fair game

Step-by-step explanation:

The first thing we need to have here is the sample space. This refers to the set of all possible results that can occur from the rolling.

Please check attachment for this

Kindly note that the total number of possible outcomes is 36.

And in the attachment, sums which are divisible by 3 are circled.

The number of circles we can count is 12

Thus, the probability of you winning would be number of circles/total number of outcomes = 12/36 = 1/3

Is it a fair game?

No, it is not

It can only be a fair game if the probability of winning equals probability of losing ( which is 18/36 = 1/2 or 0.5)

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2 years ago
Purnima took a loan of RS.100,000 from bank at the rate of 10 % compound interest . Immediately she lent the whole amount to her
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Answer:

RS 44,000

Step-by-step explanation:

The compound interest formula is FV = PV(1 + r)ⁿ. Where FV = Future value, PV = present value, r = rate and n = no of years.

Since Purnima loans RS 100,000, PV = 100,000. Which is the amount she lends to her friend. She lends to her friend at a rate of 10% compound half yearly which equals r = 10% ÷ 1/2 year = 20% per year = 0.2. Since she lends her friend for two years, n = 2.

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So, her profit is FV - PV = 144,000 - 100,000 = RS 44,000

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1 year ago
In isosceles △ABC (AC = BC) with base angle 30° CD is a median. How long is the leg of △ABC, if sum of the perimeters of △ACD an
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Note necessary facts about isosceles triangle ABC:

  • The median CD drawn to the base AB is also an altitude to tha base in isosceles triangle (CD⊥AB). This gives you that triangles ACD and BCD are congruent right triangles with hypotenuses AC and BC, respectively.
  • The legs AB and BC of isosceles triangle ABC are congruent, AC=BC.
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1. Consider right triangle ACD. The adjacent angle to the leg AD is 30°, so the hypotenuse AC is twice the opposite leg CD to the angle A.

AC=2CD.

2. Consider right triangle BCD. The adjacent angle to the leg BD is 30°, so the hypotenuse BC is twice the opposite leg CD to the angle B.

BC=2CD.

3. Find the perimeters of triangles ACD, BCD and ABC:

P_{ACD}=AC+CD+AD=2CD+CD+AD=3CD+AD;

P_{BCD}=BC+CD+BD=2CD+CD+AD=3CD+AD;

P_{ABC}=AC+BC+AB=2CD+2CD+AD+BD=4CD+2AD.

4.  If sum of the perimeters of △ACD and △BCD is 20 cm more than the perimeter of △ABC, then

P_{ACD}+P_{BCD}=P_{ABC}+20,\\ \\3CD+AD+3CD+AD=4CD+2AD+20,\\ \\6CD+2AD=4CD+2AD+20,\\ \\2CD=20.

5. Since AC=BC=2CD, then the legs AC and BC of isosceles triangles have length 20 cm.

Answer: 20 cm.

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Answer:

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Step-by-step explanation:

The dimensions of the original photo were 11 inches by 11 inches.

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