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attashe74 [19]
1 year ago
6

A quality control officer randomly checking weights of pumpkin seed bags being filled by an automatic filling machine. Each bag

is advertised as weighing 400 grams. A bag must weigh within 2.1 grams in order to be accepted. What is the range of rejected bag, x, for the bags of pumpkin seeds?
A. 397.9 B. x < 397.9 and x > 402.1
C. x < 400.0 and x> 402.1
D. 400.0 > x < 402.1
Mathematics
2 answers:
Vesnalui [34]1 year ago
8 0
<h2>Answer:</h2>

Option: B is the correct answer.

    B. x < 397.9 and x > 402.1

<h2>Step-by-step explanation:</h2>

It is given that:

Each bag is advertised as weighing 400 grams.

Also, a  bag must weigh within 2.1 grams in order to be accepted.

Hence, for the bag being accepted the weight must be no less than 2.1 gram from 400 gram and should be no more than 2.1 gram from 400 grams.

i.e. the weight of the bag must be such that:

               400-2.1≤ x ≤ 400+2.1

i.e.

              397.9 ≤ x ≤ 402.1

Hence, if the weight of the bag is less than 397.9 grams or is more than 402.1 grams then the bag will be rejected.

i.e. The range for the bag being rejected is: x<397.9 grams and x>402.1 grams.

GarryVolchara [31]1 year ago
7 0
From 0g to 494.7g are rejected as well as those heavier than 505.3grams.

You calculate this by subtracting and adding 5.3 to 500
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Janie ordered boxed lunches for a student advisory committee meeting. Each lunch costs $4.25. The total cost of the lunches is $
andriy [413]

Answer:

11 boxed lunches

Step-by-step explanation:

Full question

Janie ordered boxed lunches for a student advisory committee meeting. Each lunch cost 4.25. The total cost of the lunches is 53.75, including a 7$ delivery fee. Write and solve an equation to find x the number of boxed lunches Janie ordered

First of all subtract the delivery feesince it was inckuded in the total cost, this will now be the total cost of all the noxed lunches ordered by Janie, then divide the balance of the total cost by the cost of one boxed lunch to get thd total boxed kunches

X= 53.75-7/4.25

X= 53.75-7= 46.75/4.25

X=11

7 0
1 year ago
Read 2 more answers
Using the midpoint method, find the cross-price elasticity of demand for FedEx and UPS overnight shipping if the price of FedEx
IrinaK [193]

Answer:

Cross price elasticity using midpoint method = 0.56

Step-by-step explanation:

Using the mid-point method

Cross-price Elasticity of Demand = <u>% change in Quantity demanded of UPS</u>

                                                          % change of price of FedEx

%change in Quantity demanded of UPS

using Mid-point method                          = <u> Q2-Q1           </u>  × 100

                                                                     (Q1+Q2)÷ 2

                                      = <u>1.3-1.2           </u>   × 100

                                        (1.2+1.3)÷2

                                     = <u>0.1      </u> × 100

                                       1.25

                                     = 8%

% change in price of FedEx

using midpoint method    =<u> P2-P1            </u>× 100

                                             (P1+P2)÷ 2

                                          =<u> 75-65           </u>× 100

                                            (65+75)÷2

                                          =<u> 10  </u>   × 100

                                             70

                                          = 14.28%

Cross-price Elasticity of Demand =  8% ÷ 14.28%

using midpoint method                = 0.56

             

6 0
1 year ago
A rectangle has height and width changing in such a way that the area remains constant 2 square feet. At the instant the height
hichkok12 [17]

Answer:

\frac{1}{3} ft/min is the rate of changing of width

Step-by-step explanation:

Given -

The area always remain constant i.2 2 square feet.

Height of the rectangle = 2 feet

Rate of changing of height = 6 feet per minute

Since area is constant

2 sq ft = (2 * 6) ft/min * 1 * x ft/min

x = \frac{1}{3} ft/min

4 0
1 year ago
The rate of transmission in a telegraph cable is observed to be proportional to x2ln(1/x) where x is the ratio of the radius of
sergij07 [2.7K]

Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

f'(x) = k*((x^2)'*ln(1/x) + x^2*(ln(1/x)')) = k*(2x\,ln(1/x)+x^2*(\frac{1}{1/x}*(-\frac{1}{x^2})))\\= k * (2x \, ln(1/x)-x)

We need to equalize f' to 0

  • k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
  • 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
  • 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
  • ln(1/x) = x/2x = 1/2 -------  we send the natural logarithm as exp
  • 1/x = e^(1/2)
  • x = 1/e^(1/2) = 1/√e ≅ 0.607

Thus, the value of x that gives the maximum transmission is 1/√e.

7 0
2 years ago
Solve for m:<br> -3(1 – 5m) = — 38 + 8m
Solnce55 [7]

Answer:

m = - 5

Step-by-step Explanation:

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3 0
1 year ago
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