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solmaris [256]
2 years ago
11

Which of the following is a step in simplifying the expression x multiplied by y to the power of 4 over x to the power of negati

ve 5 multiplied by y to the power of 5, the whole to the power of negative 3.? (5 points)
Group of answer choices

x to the power of negative 3 multiplied by y to the power of negative 12, the whole over x to the power of 15 multiplied by y to the power of negative 15.

x to the power of negative 3 multiplied by y, the whole over x to the power of negative 8 multiplied by y to the power of 2.

x to the power of negative 3 multiplied by y, the whole over x to the power of negative 5 multiplied by y to the power of 5.

x to the power of negative 3 multiplied by y to the power of negative 12, the whole over x to the power of negative 5 multiplied by y to the power of 5.

Flag this Question
Question 6
Mathematics
1 answer:
vodomira [7]2 years ago
4 0

Answer:

x to the power of negative 3 multiplied by y to the power of negative 12, the whole over x to the power of 15 multiplied by y to the power of negative 15.

Step-by-step explanation:

Given:

(\frac{xy^4}{x^{-5}y^5} )^{-3}

We need to simplify the equation.

As while solving these kind of problems, keep in mind the following Law on Indices:

1. (a^m)^n=a^{mn}

Applying the same we get;

\frac{x^{-3}(y^4)^{-3}}{(x^{-5})^{-3}(y^5)^{-3}}\\\\\frac{x^{-3}y^{4\times-3}}{x^{-5\times-3}y^{5\times-3}} \\\\\frac{x^{-3}y^{-12}}{x^{15}y^{-15}}

Final Answer:

x to the power of negative 3 multiplied by y to the power of negative 12, the whole over x to the power of 15 multiplied by y to the power of negative 15.

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A force of 500.0 is represented graphically with its tail at the origin and the tip pointed in a direction 30.0° above the posit
trapecia [35]

Answer:

F^{'}=(250\sqrt{3},250 })

Step-by-step explanation:

We have F´ =500 and \alpha=30º, so x and y components:

F´ = (F_{x} , F_{y}) this is

F_{x} = F^{'} *Cos\alpha

F_{y} = F^{'} *Sin\alpha  

F_{x} = F`*Cos\alpha =500*Cos30=500*\frac{\sqrt{3} }{2} =250\sqrt{3}

F_{y}=F*Sin\alpha  =500*Sin30=500*\frac{1}{2}=250;

Finally

F' = (250\sqrt{3} , 250)

3 0
2 years ago
Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in
Hitman42 [59]

Answer:

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

Step-by-step explanation:

We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                         P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of Americans who decide to not go to college = 48%

           n = sample of American adults = 331

           p = population proportion of Americans who decide to not go to

                 college because they cannot afford it

<em>Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.</em>

<em />

<u>So, 90% confidence interval for the population proportion, p is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                        of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.645) = 0.90

P( -1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \hat p-p < 1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

P( \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

<u>90% confidence interval for p</u> = [ \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.48 -1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } } , 0.48 +1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } } ]

 = [0.4348, 0.5252]

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.

3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.

So, the margin of error =  Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }

              0.015 = 1.645 \times \sqrt{\frac{0.48(1-0.48)}{n} }

              \sqrt{n}  = \frac{1.645 \times \sqrt{0.48 \times 0.52} }{0.015}

              \sqrt{n} = 54.79

               n = 54.79^{2}

               n = 3001.88 ≈ 3002

Hence, a survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

5 0
2 years ago
The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in
Gnesinka [82]
First, determine the center of the circle by getting the midpoint of the points given for the circumference.
                    midpoint = ((0 + 0)/2, (3 + -4)/2)
                          midpoint (0, -0.5)
Then, we get the radius by determining the distance from either of the circumferential point to the center. 
                        radius = √(0 -  0)² + (3 +4)²  = 7
The equation for the circle would be,
                        x² + (y + 0.5)² = 7²
8 0
2 years ago
Grace has 1.35 pounds of strawberries, 1.4 pounds of bananas, and some apples. She has more pounds of apples than pounds of stra
satela [25.4K]

Answer:

Grace could have 1.36 pounds, 1.37 pounds, 1.38 pounds or 1.39 pounds of apples.

Step-by-step explanation:

Let a represent pounds of apples.

We have been given that Grace has 1.35 pounds of strawberries. She has more pounds of apples than pounds of strawberries.

This means that a is greater than 1.35. We can represent this information in an inequality as:

a>1.35

We are also told that Grace has 1.4 pounds of bananas. She has fewer pounds of apples than pounds of bananas. This means that a is less than 1.4. We can represent this information in an inequality as:

a

Upon combining both inequalities, we will get:

1.35

Therefore, Grace could have 1.36 pounds, 1.37 pounds, 1.38 pounds or 1.39 pounds of apples.

6 0
2 years ago
The percentage of people given an antirheumatoid who suffer severe, moderate, or minor side effects are 11, 20 and 69%, respecti
Snowcat [4.5K]

Answer:2.9235

Step-by-step explanation:

Since 20 people are administered the medicine and;

11% of the 20 people suffer severe i.e 11% of 20 = 2.2 people

20% of them suffer moderate i.e

20% of 20 = 4 people and;

69% of the 20 people suffer minor side i.e

69% of 20 = 13.8 people

Therefore the probability 2, 4, and 14 people will suffer severe, moderate, or minor side effects, respectively will be;

2/2.2 + 4/4 + 14/13.8 (i.e possible outcome/total outcome)

This will give us 2.9235

6 0
2 years ago
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