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2 years ago

Which explains why Ramone’s equation has no solution?

Mathematics

2 answers:

kvv77 [185]2 years ago

8 0

The matrices must be the same size

Good luck

Anestetic [448]2 years ago

5 0

Answer:

B.The matrix must be of the same size in order to perform addition or subtraction.

Step-by-step explanation:

We are given that Ramone's wrote the following matrix equation

$A+\left[\begin{array}{ccc}8\\-12\\3\end{array}\right]=\begin{bmatrix}0&18&-21\end{bmatrix}$

We have to explain why Ramone's equation has no solution

$A=-\left[\begin{array}{ccc}8\\-12\\3\end{array}\right]+\begin{bmatrix}0&18&-21\end{bmatrix}$

Using subtraction property of equality

We can not solve because order of I matrix $3\times 1$ and order of second matrix $1\times 3$ .

If the order of two matrix are same then the matrix will be added or subtract.The necessary condition for addition or subtraction of matrix is order of matrix should be same.

Hence, option B is true.

Answer:B.The matrix must be of the same size in order to perform addition or subtraction.

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Two wires with lengths of 448 cm and 616 cm are to be cut into pieces of all the same length without a remainder. Find the great

Y_Kistochka [10]

Answer:

56 cm

Step-by-step explanation:

We need ro find the GCD of these numbers. In finding the GCD, we list the multiples of the number, beginning with the smallest number. Here, the

The factors of 616=2*2*2*7*11

The factors of 448 =2*2*2*2*2*2*7

Common factors in both are 2*2*2*7=56

Therefore, the greatest possible length is 56 cm

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2 years ago

Use the interactive number line to find the sum.<br>-5.5 + 3.7 =

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Answer: -1.8

Step-by-step explanation:

Start at -5.5 and move the point on the number line up 3.7 spaces.

Hope it helps <3

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2 years ago

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Use the geometric definition of the cross product and the properties of the cross product to make the following calculations. (a

kirill [66]

Answer:

Step-by-step explanation:

we know

$\vec{i}\times \vec{j}=\vec{k}$

$\vec{j}\times \vec{k}=\vec{i}$

$\vec{k}\times \vec{i}=\vec{j}$

(a) $\left [ \left ( \hat{i}+\hat{j}\right )\times \hat{i}\right ]\times \hat{j}$

$=\left [ \hat{i}\times \hat{i}+\hat{j}\times \hat{i}\right ]\times \hat{j}$

$=\left [ 0-\hat{k}\right ]\times \hat{j}$

$=\hat{i}$

(b) $\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{j}\times \hat{k}\right )$

$=\left ( \hat{j}+\hat{k}\right )\times \left ( \hat{i}\right )$

$=\hat{k}+\hat{j}$

$=4\hat{i}\times \hat{i}+4\hat{i}\times \hat{j}$

$=0+4\hat{k}$

(d) $\left ( \hat{k}+\hat{j}\right )\times \left ( \hat{k}-\hat{j}\right )$

$=\hat{k}\times \hat{k}-\hat{k}\times \hat{j}+\hat{j}\times \hat{k}-\hat{j}\times \hat{j}$

$=0+\hat{i}+\hat{i}-0$

$=2\hat{i}$

6 0

2 years ago

Cassie made a picture graph to record the points that third grade students scored on test.Mrs Wilson's group scored 40 points in

lara31 [8.8K]

Answer:

4 students scored 3 points each

7 students scored 4 points each

Step-by-step explanation:

<u>Undetermined equations </u>

There are problems where there are not enough data to provide a unique (determined) solution. We form as many equations as possible and try to find the combination of values of the variables to fulfill all the conditions

For this question, we are assuming the grades go from 1 to 5. We know 11 students in Mrs. Wilson's group scored 40 points in all. We must find a combination of points to produce a sum of 40. We're also assuming only integer points can be scored.

To make things easier, let's find the mean value of the total scores: 40/11=3.6

If we stick to the closest integer near 3.6 we can find a quick solution. Let's think all the students scored 4. It would give a total of 44 points (4 more than required). To adjust the excess, we simply set the score of 4 students to 3 points. Our solution will be

4 students scored 3 points each: 12 points

7 students scored 4 points each: 28 points

Total: 40 points

Note: You can find more solutions apart from this one. For example, set the score of one of the 4-points students to 3. To compensate, set another one from that group to 5 points. Our new solution will be

5 students scored 3 points each: 15 points

5 students scored 4 points each: 20 points

1 student scored 5 points : 5 points

It also has a total of 40 points from 11 students

6 0

2 years ago

Riko wants to find the distance between the points (−2, −3) and (2, −5). His work is shown. Riko correct? Explain why or why not

nadya68 [22]

Answer:

I'm guessing you want to know the distance I think so the distance is √20

Step-by-step explanation:

Distance formula

√(x2-x1)^2+(y2-y1)^2

√(2-(-2)^2+(-5-(-3)^2

√16+4= 20

√20

finding the square root gives you a long decimal which is 4.472135954999 and so on

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2 years ago

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