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Dmitry_Shevchenko [17]
1 year ago
14

A website randomly selects among 10 products to discount each day. The color printer of interest to you is discounted today. Det

ermine the following:_______.
(a) What is the probability that this product is first discounted again exactly 10 days from now?
(b) What is the expected number of days until this product is again discounted?
Mathematics
1 answer:
Varvara68 [4.7K]1 year ago
6 0

Answer:

a) P = 0.039

b) The expected number of days is 10 days.

Step-by-step explanation:

The most appropiate distribution to use in this case is the geometric distribution, in order to calculate the probability of a success after k failure trials.

The probability of success, as each of the 10 products are assumed to have fair probabilities, is:

p=1/10=0.1

Then, the probability that our product is not selected any given day is:

q=1-p=1-0.1=0.9

a) The probability that exactly this product is selected exactly 10 days from now is the probability that is not selected (probbility q) for the next 9 days and selected (probability p) at the 10th day:

P=q^9p^1=0.9^9\cdot0.1=0.3874\cdot0.1=0.039

b) The expected number of days is calculated as:

E(X)=\dfrac{1}{p}=\dfrac{1}{0.1}=10

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Find the point (x,y) of x2+14xy+49y2=100 that is closest to the origin and lies in the first quadrant.
Gala2k [10]

Notice that

x^2+14xy+49y^2=(x+7y)^2

so the constraint is a set of two lines,

(x+7y)^2=100\implies\begin{cases}x+7y=10\\x+7y=10\end{cases}

and only the first line passes through the first quadrant.

The distance between any point (x,y) in the plane is \sqrt{x^2+y^2}, but we know that \sqrt{f(x,y)} and f(x,y) share the same critical points, so we need only worry about minimizing x^2+y^2. The Lagrangian for this problem is then

L(x,y,\lambda)=x^2+y^2+\lambda(x+7y-10)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0

L_y=2y+7\lambda=0

L_\lambda=x+7y-10=0

We have

L_y-7L_x=2y-14x=0\implies y=7x

which tells us that

x+7y-10=0\iff x+49x=10\implies x=\dfrac15\implies y=\dfrac75

so that \left(\dfrac15,\dfrac75\right) is a critical point. The Hessian for the target function x^2+y^2 is

H(x,y)=\begin{bmatrix}2&0\\0&2\end{bmatrix}

which is positive definite for all x,y, so the critical point is the site of a minimum. The minimum distance itself (which we don't seem to care about for this problem, but we might as well state it) is \sqrt{\left(\dfrac15\right)^2+\left(\dfrac75\right)^2}=2.

3 0
2 years ago
Find the product: (30 gallons 3 quarts 1 pint) × 5
SpyIntel [72]
30 gallons * 5 = 150 gallons

3 quarts * 5 = 15 quarts 

1 pint * 5 = 5 pints

Four quarts in a gallon: 15/4 = 3 gallons, 2 quarts

2 pints in a quart: 5/2 = 2 quarts, 1 pint

2 quarts + 2 quarts = 1 gallon

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4 0
2 years ago
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From home, Mary’s work is two thirds along the way to training. Training is 2.5km from work. Mary normally goes to work, then tr
polet [3.4K]
First thing to do is to illustrate the problem, Since it was mentioned that work was along the way to training, the order is shown in the picture. Mary's home and workplace are nearer compared to her training center. It is also mentioned that the distance between work and home, denoted as x, is 2/3 of the total distance from home to training. The total distance is (x + 2.5). Thus,

x = 2/3(x+2.5)
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1/3 x = 5/3
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Thus, the distance from home to work is 5 km. This means that Mary has to walk this distance twice to return home to get her shoes. Then, she will travel again the total distance of 5+2.5 = 7.5 km to get to her training center. So,

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3 0
1 year ago
Two quadrilaterals are congruent. One has vertices P, N, O, and M, and the other has vertices S, T, V, and U. These correspondin
Bogdan [553]

Answer: NPOM \cong VUTS and OPNM \cong TVUS will be correct.

Explanation:

Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent,  where, OM is congruent or equal to TS and \angle P\cong \angle U.

in quadrilaterals NPOM and  VUTS-

since, the condition \angle P = \angle U

and, side UV=side  OM   follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

similarly, these two conditions also follow in the case of OPNM \cong TVUS

we can understand it by making the figures.


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1 year ago
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Marysya12 [62]
The answer is 150 because 
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