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Musya8 [376]
2 years ago
6

Billy Jo's school is selling tickets to a Fall Festival. On the first day of ticket sales the school sold 3 adult ticket and 8 s

tudent tickets for a total of $72. The school took in $152 on the second day by selling 7 adult tickets and 16 student tickets. How much is a student ticket?
Mathematics
1 answer:
denis23 [38]2 years ago
6 0

Answer:

Y = 6

Step-by-step explanation:

On the first day of ticket sales the school <em><u>sold 3 </u></em>adult ticket and <em><u>8 student </u></em>tickets for a <em><u>total of $72</u></em>. The school took in <em><u>$152</u></em> on the second day by selling<em><u> 7 adult tickets and 16 student tickets.</u></em> How much is a student ticket?  

Day 1: 3x + 7y = 72

Day 2: 7x + 16y = 152

This becomes a system of equations.

3x+8y=72

3x+8y+−8y=72+−8y (Add -8y to both sides)

3x=−8y+72

3x/3 =  −(8y+72)/3

X = (-8/3) y + 24

Substitute  (-8/3) y + 24 for x in7x+16y=152:

7(-8/3 y + 24) + 16y = 152

-8/3 y + 168 = 152 (Simplify both sides of the equation)

-8/3 y + 168 − 168 = 152 + (−168) (Add -168 to both sides)

-8/3 y = -16

(-8/3 y)/(-8/3 y) = -16/ -8/3 y (Divide both sides by (-8)/3)

<u><em>y = 6</em></u>

<em>If you wanted to keep going...</em>

Substitute 6f or y in x = (-8/3) y + 24

(-8/3) y + 24  =  (-8/3) (6) + 24

SImplify: x = 8

<em>X = 8 and </em><u><em>Y = 6</em></u>

<u><em></em></u>

Hope this helps! <em>♥</em>

<u><em>~A.W.E.</em></u><em>S.W.A.N~</em>

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Serggg [28]
18 pears subtract by 2 wich will equal 16 pears...

18-2=16
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2 years ago
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A group of 5 friends decides to share the cost of a party together. If the party costs $1,100, how much does each friend pay?
seraphim [82]

Answer:

1,100 dollars divided by 5 friends is 220 dollars so each friend would have to pay 220 dollars

Step-by-step explanation:


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1 year ago
Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t
Ber [7]

Answer:

The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of time until the next student will arrive in the library parking lot at the university.

The random variable <em>X</em> follows an Exponential distribution with mean, <em>μ</em> = 4 minutes.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda e^{\lambda x};\ x\geq 0, \lambda >0

The parameter of the exponential distribution is:

\lambda=\frac{1}{\mu}=\frac{1}{4}=0.25

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10}{0.25e^{-0.25x}}\, dx

                 =0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821

Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

3 0
2 years ago
Solve: the quantity 3x minus 15 divided by 2 = 4x
Anon25 [30]

Answer:

x=-3

Step-by-step explanation:

(3x-15)/2 = 4x

Multiply each side by 2

(3x-15)/2 *2= 4x*2

3x-15 = 8x

Subtract 3x from each side

3x-15-3x = 8x-3x

-15 = 5x

Divide each side by 5

-15/5 = 5x/5

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5 0
2 years ago
in a certain class, 22 pupils take one or more of chemistry, economic, government. 12 take economic (E), 8 take government (G) a
mash [69]

Answer:

ai) n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) see attachment

bi) n(C⋂G) = x = 1

bii) n(G) only = 3

Step-by-step explanation:

Let chemistry = C

Economic = E

Government = G

n(E) = 12

n(G) = 8

n(C) = 7

ai) number of pupils for economics and chemistry = 0

number of pupils for economics and government = 4

The set notation for both:

n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) find attached the Venn diagram

bi) n(C⋂G) = ?

Let number of n(C⋂G) = x

From the Venn diagram

n(C) only = 12-4 = 8

n(G) only = 8-(4+x) = 4-x

n(E) only = 7-x

n(E⋂C⋂G) = 0

n(E⋂C) = 0

n(E⋂G) = 4

Total: 8+ 4-x + 7-x + x + 0+0+4 = 22

23 -x = 22

23-22 = x

x = 1

n(C⋂G) = x = 1

Number of pupils that take both chemistry and government = 1

(bii) government only = n(G) only = 4-x

n(G) only = 4-1 = 3

Number of students that take government only = 3

8 0
1 year ago
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