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kogti [31]
2 years ago
14

Submit Test 20 Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used Drag the numbers to match e

ach equation with the value of its unknown number 6.000 40 800 400 8.000 600 6.484+2=(22) + (6,000+ 2) + (80 + 2) + (42) 4.864-2-1 * 2) + (60 + 2) + (4 + 2) + (4,000 - 2) 6.844 2-( 42) + (800-2) + (2) + (40 - 2) Reset NE
​
Mathematics
1 answer:
lesya [120]2 years ago
4 0

Answer: i don’t know I just really need need points soory for wasting your time

Step-by-step explanation.    i don’t know I just really need need points soory for wasting your time

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One month julia collected 8.4 gallons of rainwater. That month she used 5.2 gallons of rainwater to water her garden and 6.5 gal
Andru [333]

Given

One month julia collected 8.4 gallons of rainwater.

she used 5.2 gallons of rainwater to water her garden

6.5 gallons of rainwater to water flowers

Find out how much was the supply of rainwater increased or decreased by the end of the month.

To proof

As given in the question

One month julia collected 8.4 gallons of rainwater

she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers

Total water she used in the month = 5.2 gallons + 6.5gallons

                                                         = 11.7 gallons

Let the supply of rainwater increased or decreased by the end of the month

be x .

Than the equation become in the form

x + 8.4 = 11.7

x = 3.3 gallons

Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.

Hence proved



8 0
2 years ago
Read 2 more answers
a salon owner noted what types of services its clients requested last week. Here are the results. 5% dye only, 30% haircut and d
soldi70 [24.7K]

Answer:

2/3

Step-by-step explanation:

So we have 10%+5%=15% of clients under the condition "permanent", and we can find the probability that a client in that group requested a haircut:

P(haircut | permanent)=10%/15%=2/3

​

3 0
2 years ago
Suppose that the weight of navel oranges is normally distributed with a mean µµ = 8 ounces, and a standard deviation σσ = 1.5 ou
monitta

Answer:

Hello some parts of your question is missing below is the missing part

c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces

Answer: A) 0.0099

              B) 0.6796

              C) 0.13956

Step-by-step explanation:

weight of Navel oranges evenly distributed

mean ( u ) = 8 ounces

std ( б )= 1.5

navel oranges = X

A ) percentage of oranges weighing more than 11.5 ounces

P( x > 11.5 ) = P ( \frac{x - u}{ std} > \frac{11.5-8}{1.5} )

                   = P ( Z > 2.33 ) = 0.0099

                   = 0.9%

B) percentage of oranges weighing less than 8.7 ounces

  P( x < 8.7 ) = P ( \frac{x - u}{ std} > \frac{8.7-8}{1.5} )

                    = P ( Z < 0.4667 ) = 0.6796

                    = 67.96%

C ) probability of orange selected weighing between 6.2 and 7 ounces?

P ( 6.2 < X < 7 ) = P (\frac{6.2-8}{1.5} <  \frac{x - u}{ std} < \frac{7-8}{1.5} )

                          = P ( -1.2 < Z < -0.66 )

                          = Ф ( -0.66 ) - Ф(-1.2) = 0.13956

7 0
2 years ago
Write 3.01 (1 repeating) as a mixed fraction?
Advocard [28]

Answer:

3 1/100

Step-by-step explanation:

4 0
2 years ago
How many 1/2 cup servings are there in 7/8 cup of peanut butter
Semmy [17]
You must be Divide with fractions.

7/8/1/2 then flip with 1/2 to 2/1 and multiply.

And the answer is 1 and 3/4

4 0
2 years ago
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