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horrorfan [7]
1 year ago
8

One month julia collected 8.4 gallons of rainwater. That month she used 5.2 gallons of rainwater to water her garden and 6.5 gal

lons of rainwater to water flowers.How much was the supply of rainwater increased or decreased by the end of the month
Mathematics
2 answers:
Andru [333]1 year ago
8 0

Given

One month julia collected 8.4 gallons of rainwater.

she used 5.2 gallons of rainwater to water her garden

6.5 gallons of rainwater to water flowers

Find out how much was the supply of rainwater increased or decreased by the end of the month.

To proof

As given in the question

One month julia collected 8.4 gallons of rainwater

she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers

Total water she used in the month = 5.2 gallons + 6.5gallons

                                                         = 11.7 gallons

Let the supply of rainwater increased or decreased by the end of the month

be x .

Than the equation become in the form

x + 8.4 = 11.7

x = 3.3 gallons

Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.

Hence proved



kirill [66]1 year ago
5 0

Total rainwater collected by Julia = 8.4 gallons

Water used for watering garden = 5.2 gallons

Water used for watering flowers = 6.5 gallons

Hence, total water used by Julia = 5.2+6.5=11.7 gallons

11.7 gallons were used and only 8.4 gallons were collected , so supply of rainwater decreased by 11.7-8.4=3.3 gallons

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What is the final amount if 784 is decreased by 1% followed by a 4% increase?
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General Formula

<em>A way to solve this problem is as follows</em>:

The general formula for this is taking into account that:

\\ percent\;change = \frac{change}{starting\;point}

The <em>starting point</em> is number 784.

The most important key is the solution for this answer is that:

\\ change = starting\;point - x

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\\ percent\;change = \frac{starting\;point - x}{starting\;point} [1]

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We also need to evaluate the following: if a quantity decreases a percentage, and then increases in another percentage, what is the final percentage? In this case, we have first that 784 decreases by 1% and then increases by 4%. As a result 784 will +4% - 1% = +3%, that is, 784 will increase in 3%.

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\\ 0.03 * 784 = \frac{784 - x}{784}*784

\\ 0.03 * 784 = (784 - x)*\frac{784}{784}

\\ 0.03 * 784 = (784 - x)*1

\\ 0.03 * 784 = (784 - x)

Remember that if we add, subtract, multiply, divide... to both sides of the equation, we do not "alter" this equation.

Subtracting 784 to both sides:

\\ (0.03 * 784) - 784 = (784 - 784 - x)

\\ (0.03 * 784) - 784 = (0 - x)

\\ (0.03 * 784) - 784 = - x

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\\ -1 * (-760.48) = -1 * (-x)

We have to remember that:

\\ +*+ = +; - * - = +; - * + = -; + * - = -

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Then

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Difference = 31.36 - 7.84 = 23.52.

Then, we need to add this value to 784, and 784 + 23.52 = 807.52 (the same result).

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