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Grace [21]
2 years ago
8

All computers are on sale for 10% off the original price. If x is the original price of the computer, then the function that rep

resents the price after only a 10% discount is: P(x) = x - 0.1x P(x) = 0.9x The function that gives the price, C, if only a $150 coupon is used is: C(x) = x - 150 Choose the composition function that gives the final sale price after a 10% discount is followed by a $150 coupon. C(P(x)) = 0.9x – 150 P(C(x)) = 0.9x – 150 C(P(x)) = 1.9x – 150 P(C(x)) = 1.9x – 150
Mathematics
2 answers:
prohojiy [21]2 years ago
5 0
So the original price is "x".

the discounted price by 10% is P(x) = 0.9x.

the price minus a $150 coupon is C(x) = x - 150.

so, if you go to the store, the item is discounted by 10%, so you're really only getting out of your pocket 90% of that, or 0.9x, but!!! wait a minute!! you have a $150 coupon, and you can use that for the purchase, so you're really only getting out of  your pocket 0.9x - 150, namely the discounted by 10% and then the saving from the coupon.

C(   P(x)   ) = P(x) - 150

C(   P(x)   ) = 0.9x - 150
worty [1.4K]2 years ago
4 0

<em>C(P(x)) = 0.9x – 150</em> is the correct answer.

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Alternative hypothesis:p_{1} \neq p_{2}  

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Data given and notation  

X_{1}=25 represent the number of homeowners who would buy the security system

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p_{1}=\frac{25}{140}=0.179 represent the proportion of homeowners who would buy the security system

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z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

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We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17  

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