Answer:
A
Step-by-step explanation:
because the points in the plot point graph are all close to the line which indicates a strong association.
Also the slope isn't closer to 0 than to 1 so that eliminates those answers.
Answer: d
Step-by-step explanation:
Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
First, you need to determine the resultant force and its angle. This one is real easy, since you only have one (x) and one (y) component. X = 300 and Y = 480
<span>1) sqrt (300^2 + 480^2) = ? (round your answer) </span>
<span>2) tanθ = y/x Solving for θ: θ = tan^-1(y/x): θ = ? (round your answer) </span>
<span>Now, you should have a resultant force value and its angle, from zero, in the first quadrant and between the Y and N axes. Draw yourself a diagram showing all of the axes, the resultant and the angles. You're going to have to do some very easy math to determine the angles between the Y and N axes and the resultant. Call these new angles α and β. α is the angle between N and the resultant and β is the angle between T and the resultant. Hint: one of them is 28 deg. </span>
<span>Once you've gotten those figured, the Y and N axes become your new axis, ignore the X and Y. Find the X and Y components of the resultant (again). ? * cos(α) = 500 and ? * sin(β) = 266 (round your answers)</span>
