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myrzilka [38]
2 years ago
7

Every day, a lecture may be canceled due to inclement weather with probability 0.05. Class cancelations on different days are in

dependent. (a) There are 15 classes left this semester. Compute the probability that at least 4 of them get canceled. (b) Compute the probability that the tenth class
Mathematics
1 answer:
andrezito [222]2 years ago
5 0
<h3>(a)Probability of cancelling at least 4 classes  is 0.0055.</h3><h3>(b)Probability of 10th class is third class that gets cancelled  = 0.0031</h3>

Step-by-step explanation:

Here, the question is<u> incomplete</u>.

Every day, a lecture may be canceled due to inclement weather with probability 0.05. Class cancellations on different days are independent.

(a) There are 15 classes left this semester. Compute the probability that at least 4 of them get canceled.

(b) Compute the probability that the tenth class this semester is the third class that gets canceled.

Now, here:

The probability of cancelling each class  = 0.05

Now, probability of cancelling at least 4 classes

= 1 - P(Cancelling  at max 3 classes)

=  1 - P(0 ≤ x  ≤  3)   = 1 - Binomial (15,0.05,3)

= 0.0055

Hence, probability of cancelling at least 4 classes  is 0.0055.

(b) As given, 10th class is third class that gets cancelled.

So, the first and second classes that get cancelled in between 1 - 9.

P(2 class cancelled in 1st 9) = Binomial (15,0.05,3) = 0.0629

Also, as given  P(10th class cancelled) = 0.05

⇒ P(10th class is third class that gets cancelled ) = 0.0629 x 0.05 = 0.0031

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Complete Question

The complete qustion is shown on the first uploaded image

Answer:

The correct option is B

Step-by-step explanation:

From the question we are told that

      The sample size  is  n = 49

       The mean is  \mu  =  17ppb

       The standard deviation is \sigma =  14 ppb

Generally the standard error of this measurement is mathematically represented as

       \sigma_z  =  \frac{\sigma}{\sqrt{n} }      

substituting values

      \sigma_{\= x}  =  \frac{14}{\sqrt{49} }  

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Now the probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb represented as P(X < 15 )

Next is to find the z value

    z =  \frac{\mu -\sigma }{\sigma_{\= x}}

     z =  \frac{15-17}{2}

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      P(X

                       

       

     

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2 years ago
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A researcher studying koi fish collected data on three variables, A, B, and C. The following residual plots show the residual fo
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Sean has 15,000 to invest she will put some of it into a fund that pays 4.5% annual interest in the rest in a certificate of dep
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Answer:$12500 was invested into the account that pays 4.5% annual interest..

$2500 was invested into the the certificate of deposit that pays 1.8% annual interest..

Step-by-step explanation:

Let x represent the amount invested into the account that pays 4.5% annual interest.

Let y represent the amount invested into the certificate of deposit that pays 1.8% annual interest.

Sean has 15,000 to invest. She will put some of it into a fund that pays 4.5% annual interest and the rest in a certificate of deposit that pays 1.8% annual interest. This means that

x = y + 15000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

Considering the account earning 4.5% interest, the interest would be

I = (x × 4.5 × 1)/100 = 0.045x

Considering the account earning 11% interest, the interest would be

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

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