A hotel manager records the number of bookings made at various prices during July.What type of correlation does the graph show?

Herky was given the following system of equations to solve. 3 x minus 2 y = 17. x minus 3 y = 1.

ioda

Answer:

(7, 2 )

Step-by-step explanation:

Given the 2 equations

3x - 2y = 17 → (1)

x - 3y = 1 → (2)

Rearrange (2) expressing x in terms of y by adding 3y to both sides

x = 1 + 3y → (3)

Substitute x = 1 + 3y in (1)

3(1 + 3y) - 2y = 17 ← distribute and simplify left side

3 + 9y - 2y = 17

3 + 7y = 17 ( subtract 3 from both sides )

7y = 14 ( divide both sides by 7 )

y = 2

Substitute y = 2 into (3) for corresponding value of x

x = 1 + 3(2) = 1 + 6 = 7

Solution is (7, 2 )

5 0

2 years ago

Read 2 more answers

Explain how employee benefits affect total employment compensation

dlinn [17]

Employee benefits are generally considered added compensation in addition to wages or salary. so if it were represented as a function it would be C=b+w. The total compensation C would be equal to benefits b plus wages or salary w.

8 0

2 years ago

Read 2 more answers

Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th

larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

$p_v =2*P(z>0.546)=0.585$

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

$\hat p=0.2$ estimated proportion

$p_o=0.16$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>0.546)=0.585$

4 0

2 years ago

Maya bought a dozen specialty donuts at the bakery for $18. She purchased a mixture of frosted donuts for $2 each, glazed donuts

Zina [86]

Answer:

The quantity of frosted donuts = 2

The quantity of glazed donuts = 9

The quantity of custard filled donuts = 1

Step-by-step explanation: