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ZanzabumX [31]
2 years ago
8

If a line crosses the yaxis at (0, 1) and has a slope of 4/5 , what is the equation of the line?

Mathematics
1 answer:
Misha Larkins [42]2 years ago
7 0

Answer:

y=4/5x+1

Step-by-step explanation:

When making linear equations for graphs we need to fill in the model of y=mx+b. M gets filled in with the slope of line and in this case it's 4/5. X is our unknown variable that we could substitute for. B is our y-intercept which is 1 since that is where the line first touches the y-axis. Together it makes y=4/5x+1.

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Consider circle C below, where the central angle is measured in radians. Circle C is shown. Line segments R C and S C are radii.
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What is the length of the radius?

12 units

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2 years ago
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How close are a meter and a yard? Convert, 1 meter into yards by using the fact that there are 100 centimeters in a meter, 2.54
Sveta_85 [38]

Answer:

To convert 1 meter into yards

Using the given facts : 100 centimeters in a meter, 2.54 centimeters in an inch, 12 inches in a foot, and 3 feet in a yard.

we can write these as;

1 m = 100 cm

1 inches = 2.54 cm

1 ft = 12 inches and

1 yard = 3 ft

1 ft = 12 inches

3 ft = 3 \times 12 = 36 inches

Since,

1 inches  = 2.54 cm

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Also,

1 m = 100 cm

or

1 cm = \frac{1}{100} m

then;

91.44 cm = \frac{91.44}{100} =0.9144 m

⇒ 1 yards = 0.9144 m

Divide both sides by 0.9144 we get;

1 meter = \frac{1}{0.9144} = 1.0936133 yards.

Therefore, the answer is, 1 m =  1.1 yards (nearest to tenth)


5 0
2 years ago
How many ounces does a 2-ton rhinoceros weigh?
suter [353]

Answer:

64,000 ounces

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1 ton = 32,000 ounces

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6 0
2 years ago
Brenda earns $1,700 per month after taxes. She is working on her budget and has the first three categories finished.
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Answer:

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Step-by-step explanation:

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In the study of population dynamics one of the most famous models for a growing but bounded population is the logistic equation
MA_775_DIABLO [31]

Answer:

If  K is a constant of integration, then

P = {\displaystyle \frac{1}{b/a + Ke^{-at}}}

Step-by-step explanation:

According to the information of the problem we know that

{\displaystyle \frac{dP}{dt} = P(a-bP) }

Remember that in general a Bernoulli equation is an equation of the type

y' + p(x)y = q(x)y^n

And the idea to solve the equation is to substitute

{ \displaystyle v = y^{1-n}}

Now for this case

{\displaystyle \frac{dP}{dt} - Pa  = -bP^2}

Then we substitute

v = P^{1-2} = P^{-1}

Therefore

P = v^{-1}

and if you compute the derivative of that you get that

{\displaystyle \frac{dP}{dt} = -v^{-2} \frac{dv}{dt}}

Now you substitute that onto the original equation and get

{\displaystyle \frac{dP}{dt} - Pa  = -bP^2}

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If you multiply everything by  -v^2  you get that

{\displaystyle \frac{dv}{dt} + v = b }

That's a linear differential equation and the solution would be

v = {\displaystyle \frac{b}{a} + Ke^{-at}} = P^{-1}

Where K is a constant of integration, then

P = {\displaystyle \frac{1}{b/a + Ke^{-at}}}

3 0
2 years ago
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