Answer:
P ( x_bar > 335 ) = 0.9826
Step-by-step explanation:
Given:
- Mean amount u = 350
- standard deviation s.d = 45/year
- Sample size n = 40
Find:
- The probability of sample mean P( x_bar > 335 )
Solution:
- P ( x_bar > 335 ) = P ( Z > sqrt(n)*(x_bar - u)/s.d)
= P ( Z > sqrt(40)*(335-350)/45)
= P ( Z > -2.111) = P ( Z < 2.111)
= 0.5 + P( 0 < Z < 2.111)
= 0.5 + 0.4826
= 0.9826
Answer:

Step-by-step explanation:
The Given question is INCOMPLETE as the statements are not provided.
Now, let us try and solve the given expression here:
The given expression is: 
Now, the BINOMIAL EXPANSION is the expansion which describes the algebraic expansion of powers of a binomial.
Here, 
or, on simplification, the terms of the expansion are:

The above statement holds for each n > 0
Hence, the complete expansion for the given expression is given as above.
Answer:
2/7 or 0.2857
Step-by-step explanation:
The expected time before the first bulb burns out (two bulbs working) is given by the inverse of the probability that a bulb will go out each day:

The expected time before the second bulb burns out (one bulb working), after the first bulb goes out, is given by the inverse of the probability that the second bulb will go out each day:

Therefore, the long-run fraction of time that there is exactly one bulb working is:

There is exactly one bulb working 2/7 or 0.2857 of the time.
Answer: The theoretical probability of choosing a tile with letter P =0.18
Step-by-step explanation:
Given word = MISSISSIPPI
Total number of letters in given the word = 11
Number of letter P in given word = 2
Let A be a event of choosing a tile with a letter P then
P(A) =Number of tiles with letter P / Total letters in given word
= 2 /11 = 0.18