Answer:
Monthly household expenditures on groceries
Step-by-step explanation:
The response variable is the one for which measurements are desired and that depends on other variables.
In this case, family size, household income, and household neighborhood are independent variables, while the response variable is the monthly household expenditures on groceries.
Answer:
The probability that they are both male is 0.424 (3 d.p.)
Step-by-step explanation:
The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter
Prob (1st male) = 8 ÷ 12 = 0.667
Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.
Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636
Therefore,
Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424
68 is the correct answer. Thank you for your help! Love doing this!
∑ 4 * 5^(i-1) = 4 + 20 + 100 + 500 = 624
∑ 3 * 4^(i-1) = 3 + 12 + 48 + 192 + 768 = 1,023
∑ 5* 6^(i-1) = 5 + 30 = 35
∑ 5^(i-1) = 1 + 5 + 25 + 125 = 156
Answer:
∑ (i=1, 2) 5 * 6^(i-1) < ∑ (i=1, 4) 5^(i-1) < ∑ (i=1, 4) 4 * 5^(i-1) <
< ∑ (i=1, 5) 3 * 4^(i-1)
First part of the race
speed1, s1 = 8.75 km/h
distance1 = 5 km - x
time 1 = 0.65 h - t
Second part of the race
speed2, s2 = 6 km/h
distance2 = x
time2 = t
s2 = x/t = 6 ⇒ t = x / 6
s1 = [5 - x] / [0.65 - t] = 8.75
5 - x = 8.75 [0.65 - t]
5 -x = 8.75(0.65) - 8.75t
5 - x = 5.6875 - 8.75 (x/6)
5 - x = 5.6875 - 1.4583x
1.4583 x - x = 5.6875 - 5
0.4583 x = 0.6875
x = 0.6875 / 0.4583 = 1.5
