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1 year ago

5

The following table contains data collected on the math averages of seniors in high school and their math averages as freshman i

n college. Make a scatter plot and determine if there is a correlation between the two variables.

1 answer:

vichka [17]1 year ago

3 0

Where's the table?....

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Metro buses are scheduled to arrive at each stop every 30 minutes. If the time a person waits at a bus stop is uniformly distrib

Nutka1998 [239]

Answer:

The probability is $P(X > 25 ) = 1.667$

Step-by-step explanation:

From the question we are told that

The maximum wait is $b = 30 \ minutes$

The minimum wait would be $a = 0\ minutes$

Generally the probability that you will wait more than 25 minutes for a bus is mathematically represented as

$P(X > 25 )$

Now given that the time a person waits is uniformly distributed and that the maximum is 30 then we can evaluate the above probability as

$P(X > 25 ) = P(25 < X < 30 ) = \frac{30 - 25}{30 - 0}$

$P(X > 25 ) = 1.667$

4 0

1 year ago

Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet,

masha68 [24]

Well the sides of these 2 quadrilaterals are proportional to each other , so you would have to find the scale factor of the 2 then see which sides have already proportional pairs , then multiply *or / to find the last one .

Answer: D. 11.7 ft

5 0

1 year ago

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A cosmetic company tested a new lotion. Of the 2,500 people tested 15 had an allergic reaction. What percentage of the people ha

Aliun [14]

0.6%. 100% divided by 2,500 people means each person is worth 0.04%. 0.04 times 15 is 0.6

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1 year ago

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A store manager is looking at past jewelry sales to determine what sizes of rings to keep in stock. The list shows the ring size

Rom4ik [11]

Mean: ( 9 + 7 + 6.5 + 7.5 + 7 + 8 + 5 + 6 + 7.5 + 8 ) : 10 = 7.15
Variance:
(Sigma)² = ( 1.85² + 0.15² + 0.65² + 0.35² + 0.15² + 0.85² + 2.15² + 1.15² + 0.35² + 0.85² ) : 10 ≈ 1.15
Answer: C ) 1.15

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2 years ago

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In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegeta

alukav5142 [94]

Answer:

$Z_{0.05}=1.645$

Step-by-step explanation:

Given :In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegetables, and 458 reported that they preferred eating vegetables.

To Find :What value of z should be used to calculate a confidence interval with a 95 % confidence level?

Solution:

Confidence level = 95 % i.e.0.95

So, significance level = 5% i.e. 0.05

So, the value of z corresponding to significance level 0.05 should be used to calculate a confidence interval with a 95 % confidence level

So, $Z_{0.05}=1.645$

Hence z should be 1.645 to calculate a confidence interval with a 95 % confidence level.

4 0

1 year ago