Answer:
LCL = 59.26 to two decimal places
Step-by-step explanation:
Here, we want to estimate the LCL of the population mean with 90% confidence
We proceed as follows;
Given alpha = 0.1, then Z(0.05)=1.645 (from standard normal table), s = 15
Mathematically;
LCL =x_bar -Z*s/√( n)= 62 - (1.645 * 15)/√81
LCL = 62- (24.675)/9 = 59.2583
LCL = 59.26 to two decimal places
Answer:
One sample t-test for population mean would be the most appropriate method.
Step-by-step explanation:
Following is the data which botanist collected and can use:
- Sample mean
- Sample Standard Deviation
- Sample size (Which is 10)
- Distribution is normal
We have to find the best approach to construct the confidence interval for one-sample population mean. Two tests are used for constructing the confidence interval for one-sample population mean. These are:
- One-sample z test for population mean
- One-sample t test for population mean
One sample z test is used when the distribution is normal and the population standard deviation is known to us. One sample t test is used when the distribution is normal, population standard deviation is unknown and sample standard deviation is known.
Considering the data botanist collected, One-sample t test would be the most appropriate method as we have all the required data for this test. Using any other test will result in flawed intervals and hence flawed conclusions.
Therefore, One-sample t-test for population mean would be the most appropriate method.
Answer:
Step-by-step explanation:
Given the equation as
apply multiplication property of equality where you multiply every term by 5
3x-15=60------------------apply addition property of equality
3x-15+15=60+15
3x=75--------------------------appy division property of equality by dividing both sides by 3
3x/3=75/3
x=25
Answer:
Ramon would need 27 bags
Step-by-step explanation:
This is because if you divide 6.75 by 0.25 you would get 27
The original price of the ring is <span>£</span>1400
