First, we convert the given radius of the wheel to meters giving us an answre of 0.325 m. Then, we calculate for the circumference.
C = 2πrr
Substituting,
C = 2π(0.325 m) = 2.04 m
Then, we have a road that is 40 m long, the number of complete revolutions is,
n = 40/2.04 m = 20
Angle AQB is x = 90
Angle ASB is x = 90
Angle ALB is x = 90
Angle ATB is x = 90
Angle ARB is x = 90
<span>BWD is x < 90</span>
To graph it, just graph

and

and see where they intersect
I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it
hmm
multiply both sides by -1

multiply both sides by



minus 1 from both sides and minus 6(3^x) from both sides

use u subsitution

we can rewrite it as

now factor
I mean use quadratic formula
for

so for 0=u^2-16u-1, a=1, b=-16, c=-1


remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor


if you take the log base 3 of both sides you get

if you use ln then

then
Answer:
the probability that the project will be completed in 95 days or less, P(x ≤ 95) = 0.023
Step-by-step explanation:
This is a normal probability distribution question.
We'll need to standardize the 95 days to solve this.
The standardized score is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ
x = 95 days
xbar = mean = 105 days
σ = standard deviation = √(variance) = √25 = 5
z = (95 - 105)/5 = - 2
To determine the probability that the project will be completed in 95 days or less, P(x ≤ 95) = P(z ≤ (-2))
We'll use data from the normal probability table for these probabilities
P(x ≤ 95) = P(z ≤ (-2)) = 0.02275 = 0.023
P ( A ∩ B ∩ C) = 1/365
P(A) = 1/365, P(B)= 1/365, P(C) = 365
If events A,B and C are independed then P (A ∩ B ∩ C) = P (A) P(B) P(C) must be true,
From the probabilities we have
1/365≠ 1/365 * 1/365 * 1/365
Thus, events A,B, C are not independent.