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Vilka [71]
1 year ago
14

The Rotation is a 60° rotation about O, the center of the regular hexagon. State the image of B for the following rotation. R2-R

2 = E B O
Mathematics
1 answer:
Luda [366]1 year ago
5 0

Answer: B. I got it correct on my assignment.

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Yves bought 420 tropical fish for a museum display. He bought 6 times as many parrotfish as angelfish. How many of each type of
ohaa [14]
The answer would be d , because you have to add how many of each fish to equal up to the sum of 420 . which is x y . so the first equation is x + y = 420 . then it says he bought 6 times as many parrotfish as he did angelfish so you would have to multiply x which represents angelfish by 6 . to get the second equation of y = 6x .
5 0
1 year ago
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There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

188 who have taken courses in both calculus and discrete mathematics.

This means that A \cap B = 188

212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

This means that A = 345

How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

4 0
1 year ago
Solve each given equation and show your work the whether each equation has one solution, an infinite number of solutions, or no
Triss [41]
2x+4x-4=2+4x
2x+4x-4x=2+4
2x=6
x=3

25-x=15-3x-10
3x-x= 15-10-25
2x= -20
x= -10

4x=2x+2x+5x-5x
2x+2x+5x-5x-4x
0 . no solution
8 0
1 year ago
Unit 3 parallel and perpendicular lines homework 4 parallel line proofs
Alex17521 [72]

Answer:

1) c ║ d by consecutive interior angles theorem

2) m∠3 + m∠6 = 180° by transitive property

3) ∠2 ≅ ∠5 by definition of congruency

4) t ║ v                                    {}                   Corresponding angle theorem

5) ∠14 and ∠11  are supplementary         {}  Definition of supplementary angles

6) ∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem

Step-by-step explanation:

1) Statement                                {}                                     Reason

m∠4 + m∠7 = 180°                                 {}   Given

m∠4 ≅ m∠6                                {}              Vertically opposite angles

m∠4 = m∠6                               {}                Definition of congruency

m∠6 + m∠7 = 180°                                {}    Transitive property

m∠6 and m∠7 are supplementary     {}     Definition of supplementary angles

∴ c ║ d                               {}                       Consecutive interior angles theorem

2) Statement                                {}                                     Reason

m∠3 = m∠8                                 {}           Given

m∠8 + m∠6 = 180°                {}                 Sum of angles on a straight line

∴ m∠3 + m∠6 = 180°               {}               Transitive property

3) Statement                                {}                                     Reason

p ║ q                                 {}                    Given

∠1 ≅ ∠5                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠2 ≅ ∠1                               {}                  Alternate interior angles theorem

∠2 = ∠1                               {}                   Definition of congruency

∠2 = ∠5                                  {}               Transitive property

∠2 ≅ ∠5                                  {}              Definition of congruency.

4) Statement                                {}                                     Reason

∠1 ≅ ∠5                                  {}                Given

∠3 ≅ ∠4                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠3 = ∠4                               {}                  Definition of congruency

∠5 ≅ ∠4                               {}                 Vertically opposite angles

∠5 = ∠4                               {}                  Definition of congruency

∠5 = ∠3                                  {}               Transitive property

∠1 = ∠3                                  {}                Transitive property

∠1 ≅ ∠3                                  {}                Definition of congruency.

t ║ v                                    {}                   Corresponding angle theorem

5) Statement                                {}                                     Reason

∠5 ≅ ∠16                                  {}              Given

∠2 ≅ ∠4                               {}                  Given

∠5 = ∠16                               {}                  Definition of congruency

∠2 = ∠4                               {}                   Definition of congruency

EF ║ GH                               {}                  Corresponding angle theorem

∠14 ≅ ∠16                               {}                Corresponding angles

∠14 = ∠16                               {}                 Definition of congruency

∠5 = ∠14                                  {}               Transitive property

∠5 + ∠11 = 180°                {}                       Sum of angles on a straight line

∠14 + ∠11 = 180°                                {}      Transitive property

∠14 and ∠11  are supplementary         {}  Definition of supplementary angles  

6) Statement                                {}                                     Reason

l ║ m                                 {}                      Given

∠4 ≅ ∠7                               {}                  Given

∠4 = ∠7                               {}                   Definition of congruency

∠2 ≅ ∠7                               {}                  Alternate angles

∠2 = ∠7                               {}                   Definition of congruency

∠2 = ∠4                                  {}               Transitive property

∠2 ≅ ∠4                               {}                  Definition of congruency

∠2 and ∠4 are corresponding angles   {} Definition

DA ║ EB                               {}                  Corresponding angle theorem

∠8 and ∠9  are consecutive  interior angles    {} Definition

∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem.

6 0
2 years ago
Yoko evaluates 7 divide 1/6 by using a related multiplication expression. Which multiplication expression should she use?
Olin [163]
\bf 7\div \cfrac{1}{6}\implies 7\cdot \cfrac{6}{1}
4 0
1 year ago
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