Remember
xyz=(x)(y)(z)
if x and y and z are all perfect cubes, xyz is also a perfect cube
remmeber
(x^n)^m=x^(mn)
so if it is perfect cube it can be factored into
(x^n)^3, such taht n is a whole number
basiclaly, see if the expoent is divisble by 3
all of them should be perfect cubes
215x^18y^3z^21
split them up to see which ones need changing
215=5*43, not a perfect cube
could be changed to 6^3, which is 216
x^18=(x^6)^3
y^3=y^3
z^21=(z^7)^3
the 215 needs to be changed
<u>ANSWER</u>

<u>EXPLANATION</u>
The given compound inequality is

We need to simplify this inequality so that we can obtain x standing alone between the inequality signs.
We add 6 through out the inequality.

This simplifies to:

We now divide through by -3 and reverse the inequality sign.

We now simplify to get:

Answer:
As per the given statement:
The region bounded by the given curves about the y-axis,
, y=0, x = 0 and x = 1
Using cylindrical shell method:
The volume of solid(V) is obtained by rotating about y-axis and the region under the curve y = f(x) from a to b is;
where 
where x is the radius of the cylinder
f(x) is the height of the cylinder.
From the given figure:
radius = x
height(h) =f(x) =y=
a = 0 and b = 1
So, the volume V generated by rotating the given region:
![V =2 \pi \int_{0}^{1} x ( 13e^{-x^2}) dx\\\\V=2\pi\left [ -\frac{13}{2}e^{-x^2} \right ]_{0}^{1}\\\\V=2\pi\left (-\frac{13}{2e}-\left(-\frac{13}{2}\right) \right )\\\\V=-\frac{13\pi }{e}+13\pi](https://tex.z-dn.net/?f=V%20%3D2%20%5Cpi%20%5Cint_%7B0%7D%5E%7B1%7D%20x%20%28%2013e%5E%7B-x%5E2%7D%29%20dx%5C%5C%5C%5CV%3D2%5Cpi%5Cleft%20%5B%20-%5Cfrac%7B13%7D%7B2%7De%5E%7B-x%5E2%7D%20%5Cright%20%5D_%7B0%7D%5E%7B1%7D%5C%5C%5C%5CV%3D2%5Cpi%5Cleft%20%28-%5Cfrac%7B13%7D%7B2e%7D-%5Cleft%28-%5Cfrac%7B13%7D%7B2%7D%5Cright%29%20%5Cright%20%29%5C%5C%5C%5CV%3D-%5Cfrac%7B13%5Cpi%20%7D%7Be%7D%2B13%5Cpi%20)
therefore, the volume of V generated by rotating the given region is 
Answer:
<em>A) (-5,7)</em>
Step-by-step explanation:
<u>Functions and Relations</u>
A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).
By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

Could you give me an example of a slope-intercept form? like the formula then I'll be able to help