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2 years ago

This chart shows what happens when each object is placed on a balance with a 10 kg weight on the other side.

Mathematics

2 answers:

dexar [7]2 years ago

8 0

9514 1404 393

Answer:

Object 1 is the heaviest object.

Step-by-step explanation:

The first column of the table tells you ...

Object 1 is heavier than the 10 kg weight

The second column of the table tells you ...

Object 2 weighs 10 kg

The third column of the table tells you ...

Object 3 is lighter than the 10 kg weight

Then the relative weights are ...

Object 1 > Object 2 > Object 3

That is, Object 1 is the heaviest object.

Harman [31]2 years ago

6 0

Answer:

Object 1 is the Heaveyist!!!!

Step-by-step explanation:

3-column table with 2 rows titled effects of each object. The first row has entries Object 1, Object 2, Object 3. The second row has entries the balance tips toward the object, the balance remains balanced, the balance tips toward the weight.

Which statement is best supported by the information in the chart?

Object 1 is the heaviest object.----------!!!!!!!!!!!!!!!!!!!!!ΨΩΩΣΡξβνζ

Object 3 is heavier than Object 1.

The weight is heavier than Object 2.

The weight is the heaviest object.

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Tarun has 4 more than the twice the number of tshirts Deepak has.Mahesh has 2 more than thrice the number of T-shirts that Tarun

Dafna11 [192]

Answer:

Deepak: 4 t-shirts,

Tarun: 12 t-shirts,

Mahesh: 14 t-shirts.

Step-by-step explanation:

Let x represent number of t-shirts that Deepak has.

Please consider the complete question.

Tarun has 4 t-shirt more than twice the number of T-shirts Deepak has. Mahesh has 2 more than thrice the number of T-shirts Deepak has. If the ratio of the t-shirt that Tarun and Mahesh have is 6 : 7, find out the number of the t-shirt each of them has.

Since Tarun has 4 t-shirt more than twice the number of T-shirts Deepak has, so the number of t-shirts that Tarun has would be $2x+4$ .

We are also told that Mahesh has 2 more than thrice the number of T-shirts Deepak has. So the number of t-shirts that Mahesh has would be $3x+2$ .

Since the ratio of the t-shirt that Tarun and Mahesh have is 6 : 7, so we can represent this information in an equation as:

$\frac{2x+4}{3x+2}=\frac{6}{7}$

Cross multiply:

$6(3x+2)=7(2x+4)$

$18x+12=14x+28$

$18x-14x+12-12=14x-14x+28-12$

$4x=16$

$x=\frac{16}{4}=4$

Therefore, Deepak has 4 t-shirts.

The number of t-shirts that Tarun has would be $2x+4\Rightarrow 2(4)+4=4+4=12$

Therefore, Tarun has 12 t-shirts.

The number of t-shirts that Mahesh has would be $3x+2\Rightarrow 3(4)+2=12+2=14$

Therefore, Mahesh has 14 t-shirts.

5 0

2 years ago

Now, solve this problem. 106% of $ _______ = $7.95

Alex787 [66]

Answer:

7.5

Step-by-step explanation:

106% of $x = $7.95

In other words,

$\frac{106}{100}$ of $x = 7.95

Multiplying both sides of the equation by $\frac{100}{106}$

$\frac{106}{100} * \frac{100}{106}$ of x = 7.95 * $[\frac{100}{106}]$

=> x = $[\frac{750}{100}]$

=> x = $[\frac{7.50}{1}]$

=> x = 7.5

Validation: 106% of 7.5 = 7.95

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2 years ago

Identify 1 and 2. Select all that apply of the following terms: acute, right, obtuse, adjacent, vertical, complementary, supplem

Grace [21]

Right angle and complementary. this cold be wrong.

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2 years ago

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A set of notations (SSS, SAS, ASA and RHS) is used to describe/prove

Olin [163]

Step-by-step explanation:

where are the triangles

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2 years ago

An experiment was performed to compare the wear of two different laminated materials. Twelve pieces of material 1 were tested by

GenaCL600 [577]

Answer:

At 0.05 level of significance, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Step-by-step explanation:

We hypothesize that mean difference between abrasive wear of material 1 and material 2 is greater than 2.

So we write the null hypothesis $H_0 : \mu_1 - \mu_2 >2$ ,

and the alternative hypothesis $H_1: \mu_1 - \mu_2 \leq 2$ .

We will find the T-score as well as the p-value. If the p-value is less than the level of significance, we will reject the null hypothesis, i.e. we will conclude that the abrasive wear of material 1 is less than that of material 2. Otherwise, we will accept the null hypothesis.

Since the variance is unknown and assumed to be equal, we will use the pooled variance

$s_p^2 = \frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2} = 20.05$ ,

where $n_1 = 12, n_2 =10, s_1 =4, s_2 = 5$ .

The mean of material 1 and material 2 are $\mu_1 =85, \mu_2=81$ respectively and mean difference $d$ is equal to 4. The hypothesize difference $d_0$ is equal to 2.

To find the T-score, we use the following formula

$T = \frac{d - d_0}{\sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2} }}$

Substituting all the values into the T-score formula gives us $T = 1.04$ , and the respective p-value is equal to 0.31. This means we have enough statistical evidence not to reject the null hypothesis, and at 5% significance level, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units.

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1 year ago