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Kisachek [45]
2 years ago
13

A concert charges $30 admission and $15 per shirt. Alyssa paid $75 at the concert for her admission and shirts. Write and solve

an equation to find the number of shirts Alyssa bought. Explain what your variable represents. A. Let x = number of admission tickets; 30x + 15 = 75; 2 tickets. B. Let x = number of admission tickets; 15x + 30 = 75; 3 tickets. C. Let x = number of shirts; 30x + 15 = 75; 2 shirts. D. Let x = number of shirts; 15x + 30 = 75; 3 shirts.
Mathematics
1 answer:
amid [387]2 years ago
8 0
D is your answer my bro
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The perimeter of the base of a regular quadrilateral prism is 60 cm, the area of one of the lateral faces is 105 cm2.
yawa3891 [41]

For a better understanding of the solution, please follow the diagram in the attached file.

A regular quadrilateral is basically a square.

So, if the base of the prism has a perimeter of 60 cm, then the length of the side of the square will be \frac{60}{4}=15 cm. It is shown of the diagram.

Now, from the diagram, it is clear that the lateral face area, which is given as 105 cm^2, is the product of the side of the square, which is known, and the unknown height, let us call it h. Thus, we will get the following equation:

15\times h=105

\therefore h=\frac{105}{15}=7 cm

This is depicted on the diagram.

Now, all our required parameters are in place. Thus, let us find what has been asked.

<u>SURFACE AREA</u>

Surface Area (SA) will be the sum of the areas of the two bases (squares) and the areas of the four lateral faces.

Since the side of one square base is 15 cm, therefore, the area of one square base will be 15^2.

Likewise, the area of one lateral surface is actually the area of a rectangle with length 15 cm and height 7 cm. Thus, it's area will be given as: 15\times 7.

Thus, our equation will be:

SA=2\times 15^2+4\times 15\times 7=870 cm^2

Therefore, Surface Area=870 cm^2

<u>VOLUME OF THE PRISM</u>

The volume of the prism will simply be the area of the base times the height of the prism.

Thus, the volume is:

Volume=15^2\times 7=1575 cm^3


5 0
2 years ago
Allen is showing his work in simplifying –8.3 + 9.2 – 4.4 + 3.7. Identify and explain any errors in his work or in his reasoning
avanturin [10]
Simplifying –8.3 + 9.2 – 4.4 + 3.7.

Identify and explain any errors in his work or in his reasoning

Original problem 1. −8.3 + 9.2 + 4.4 + 3.7

Additive inverse 2. −8.3 + 4.4 + 9.2 + 3.7 (error, not additive inverse; +3-3=0)

Commutative property 3. −8.3 + (4.4 + 9.2 + 3.7)

Associative property 4. −8.3 + 17.3

Simplify 5. 9
8 0
2 years ago
Read 2 more answers
(4 tens 3 ones) x 10
adoni [48]

To solve this problem, we must first convert all of the numbers represented by words into their numeral equivalents so we can simplify. To do this, we must remember that the ones place is the first to the left of the decimal point, and the tens place is one place farther to the left. If we have 4 tens and 3 ones, this is the same as 43 (we put the digit 4 in the tens place and the digit 3 in the ones place). If we replace our words with our new numerical value, we get:

43 * 10

To solve this, we just multiply these two numbers together, which gives us:

430

Therefore, your answer is 430.

Hope this helps!

6 0
2 years ago
Which phrase describes the perpendicular distance between two bases of a cylinder
Flura [38]

Answer:

The height of the cylinder

Step-by-step explanation:

The perpendicular distance between two bases of a cylinder is not going to be the radius or diameter of the bases (because it is BETWEEN the bases, not ON them) and it is not the area of the bases because the area of a shape cannot be a distance.

So, the only option left is the height of the cylinder, which is the correct answer.

5 0
1 year ago
A jet flies 425 km from Ottawa to Québec at rate v + 60. On the return flight, the
Marina CMI [18]

Answer:

a. \frac{- 42,500}{(v + 60)(v - 40)}

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

Initial flight rate = v + 60

Return flight rate = v - 40

t = \frac{d}{r}

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

t = \frac{d}{r}

t = \frac{425}{v + 60}

=>Flight time of the return flight:

t = \frac{425}{v - 40}

=>Difference in flight times:

\frac{425}{v + 60} - \frac{425}{v - 40}

\frac{425(v - 40) -425(v + 60)}{(v + 60)(v - 40)}

\frac{425(v) - 425(40) -425(v) -425(+60)}{(v + 60)(v - 40)}

\frac{425v - 17000 -425v - 25500}{(v + 60)(v - 40)}

\frac{425v - 425v - 17000 - 25500}{(v + 60)(v - 40)}

\frac{- 42,500}{(v + 60)(v - 40)}

3 0
2 years ago
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