There were 340,000 cattle placed on feed
How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?
Given the fraction of total cattle for 700 - 799 pounds is 2/5
Let x be the number of cattle between 700 - 799 pounds
We make a proportion using the fraction
Cross multiply it and solve for x
340000* 2 = 5x
680000 = 5x
Divide by 5 on both sides
So x= 136,000
There were 136,000 cattle between 700 and 799 pounds
Since the sum of all probabilities of all all elementary events will always be equal to 1. Furthermore, the probabilities of all mutually exclusive set of events that is part of the entire sample space will always be total of 1.
So in the problem, the answer is 1/8.
1/8 for red + 3/8 for green + 3/8 for yellow + 1/8 for blue = 8/8 or 1.
M∠X = 54.3°.
Using the Law of Sines, we have:
Cross multiplying gives us
61(sin 34) = 42(sin X)
Divide both sides by 42:
(61(sin 34))/42 = (42(sin X))/42
(61(sin 34))/42 = sin X
Take the inverse sine of both sides:
sin⁻¹((61(sin 34))/42) = sin⁻¹(sin X)
54.3 = X
B
Here, x is the volume of the 10ml solution. Multiplying it by its concentration gives the amount of alcohol in it. 50 is the total volume of the 12% solution so (50 - x) gives the volume of the 15% solution. Multiplying this by the concentration gives the amount of alcohol in it. The sum of these amounts of alcohols is equivalent to the amount of alcohol in the 12% solution which is given by the product of its volume and concentration.
