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2 years ago

14

Adrienne has several receipts from recent transactions that she entered in her records. The receipts include an ATM receipt for

a $60.00 withdrawal (plus a $2.00 transaction fee), a grocery store receipt for $32.50, and a $1,200 paycheck deposit slip. When she finishes entering her transactions, Adrienne realizes that her balance is incorrect. Assuming that Adrienne’s beginning account balance was $320.00, why is her balance incorrect?
a. Adrienne forgot to include the $2.00 ATM transaction fee.
b. Adrienne did not use $320.00 as her starting balance.
c. Adrienne deducted $23.50 from her balance instead of $32.50. d. Adrienne did not enter her ATM withdrawal correctly.

2 answers:

Rina8888 [55]2 years ago

6 0

Answer:

D.

Step-by-step explanation:

Adrienne did not enter her ATM withdrawal correctly.

svp [43]2 years ago

3 0

Answer:D

Step-by-step explanation: :)

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Destiny just received two separate gifts from her great-great-grandmother.

hichkok12 [17]

answer: 6 is the greatest number of snack bags that Destiny can make. Step-by-step

Step-by-step explanation:

The first gift is a box of 18 chocolate candy bars, and the second gift is a pack of 12 cookies.

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1 year ago

Read 2 more answers

Calculate the side lengths a and b to two decimal places

Talja [164]

Answer:

The answer is (D) ⇒ a = 11.71 , b = 15.56

Step-by-step explanation:

* In ΔABC

∵ m∠A = 45°

∵ m∠B = 110°

∴ m∠C = 180 - 45 - 110 = 25°

By using the sin Rule

∵ a/sin(A) = b/sin(B) = c/sin(C)

∵ c = 7

∴ a/sin(45) = b/sin(110) = 7/sin(25)

∴ a = (7 × sin(45)) ÷ sin(25) = 11.71

∴ b = (7 × sin(110)) ÷ sin(25) = 15.56

∴ The answer is (D)

5 0

2 years ago

The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a

maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

$\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}$

$\text{P(green swordtail)}=\dfrac{80}{140}$

$\text{P(green swordtail)}=\dfrac{4}{7}$

Therefore, the probability that the selected fish is a green swordtail is $\dfrac{4}{7}.$

B. We have to find the probability that the selected fish is male.

$\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}$

$\text{P(Male fish)}=\dfrac{36+24}{140}$

$\text{P(Male fish)}=\dfrac{60}{140}$

$\text{P(Male fish)}=\dfrac{3}{7}$

Therefore, the probability that the selected fish is a male, is $\dfrac{3}{7}.$

C. We have to find the probability that the selected fish is a male green swordtail.

$\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}$

$\text{P(Male green swordtail)}=\dfrac{36}{140}$

$\text{P(Male green swordtail)}=\dfrac{9}{35}$

Therefore, probability that the selected fish is a male green swordtail is $\dfrac{9}{35}.$

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

$\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}$

$\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}$

$\text{P(Male or green swordtail)}=\dfrac{96}{140}$

$\text{P(Male or green swordtail)}=\dfrac{24}{35}$

Therefore, the probability the selected fish is either a male or a green swordtail is $\dfrac{24}{35}.$

4 0

2 years ago

A convex lens has a diameter of 30 mm and a depth of 5 mm at the center. How far from the vertex is the focus?

natima [27]

The formula for determining the distance of the focus from the vertex is as follows,

f = x² / 4a

where f is focus, x is the radius (half the value of diameter), and a is the depth. Substituting the known values to the given equation,

f = (30/2 mm)² / (4)(5 mm)

f = 11.25 mm

<em>ANSWER: 11.25 mm</em>

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2 years ago

Which of the following is an equivalent form of the compound inequality −33 > −3x − 6 ≥ −6?

wolverine [178]

<u>ANSWER</u>

$9\: < x \leqslant0$

<u>EXPLANATION</u>

The given compound inequality is

$- 33 \: > - 3x - 6 \geqslant - 6$

We need to simplify this inequality so that we can obtain x standing alone between the inequality signs.

We add 6 through out the inequality.

$- 33 + 6\: > - 3x - 6 + 6 \geqslant - 6 + 6$

This simplifies to:

$- 27\: > - 3x \geqslant 0$

We now divide through by -3 and reverse the inequality sign.

$\frac{- 27}{ - 3} \: < \frac{ - 3x}{ - 3} \leqslant \frac{0}{ - 3}$

We now simplify to get:

$9\: < x \leqslant 0$

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2 years ago