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salantis [7]
2 years ago
14

Adrienne has several receipts from recent transactions that she entered in her records. The receipts include an ATM receipt for

a $60.00 withdrawal (plus a $2.00 transaction fee), a grocery store receipt for $32.50, and a $1,200 paycheck deposit slip. When she finishes entering her transactions, Adrienne realizes that her balance is incorrect. Assuming that Adrienne’s beginning account balance was $320.00, why is her balance incorrect?
a. Adrienne forgot to include the $2.00 ATM transaction fee.
b. Adrienne did not use $320.00 as her starting balance.
c. Adrienne deducted $23.50 from her balance instead of $32.50. d. Adrienne did not enter her ATM withdrawal correctly.
Mathematics
2 answers:
Rina8888 [55]2 years ago
6 0

Answer:

D.

Step-by-step explanation:

Adrienne did not enter her ATM withdrawal correctly.

svp [43]2 years ago
3 0

Answer:D

Step-by-step explanation:    :)

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Olaf needs a total of 3 cups of sugar to make 4 cakes. Write and solve an equation to find the number of cups of sugar he needs
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Answer:

3/4 cup

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Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form? Y = 3 (x minus seven-halves) squared minus StartFraction 27
densk [106]

Answer: y = 2 (x minus one-half) squared minus StartFraction 27 Over 2 EndFraction

or

y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

Step-by-step explanation:

Vertex form of equation : f (x) = a(x - h)^2 + k,where (h, k) is the vertex of the parabola.

y=3(x-2)^2-(x-5)^2\\\\=3(x^2+4-4x)-(x^2+25-10x)\\\\=3x^2+12-12x-x^2-25+10x\\\\=2x^2-2x-13\\\\=2(x^2-x-\dfrac{13}{2})\\\\=2(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{13}{2})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{1+26}{4})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{27}{4})=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

Hence, the vertex form of the equation is y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

8 0
2 years ago
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How do you simplify 77.28/9.2
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5 0
1 year ago
Would apreciate if someone helped me..
PtichkaEL [24]

Answer:

a). x = 11

b). m∠DMC = 39°

c). m∠MAD = 66°

d). m∠ADM = 36°

e). m∠ADC = 18°

Step-by-step explanation:

a). In the figure attached,

m∠AMC = 3x + 6

and m∠DMC = 6x - 49

Since "in-center" of a triangle is a points where the bisectors of internal angles meet.

Therefore, MC is the angle bisector of angle AMD.

and m∠AMC ≅ m∠DMC

3x + 6 = 8x - 49

8x - 3x = 49 + 6

5x = 55

x = 11

b). m∠DMC = 8x - 49

                   = (8 × 11) - 49

                   = 88 - 49

                   = 39°

c). m∠MAD = 2(m∠DAC)

                   = 2(30)°

                   = 60°

d). Since, m∠AMD + m∠ADM + m∠MAD = 180°

    2(39)° + m∠ADM + 66° = 180°

    78° + m∠ADM + 66° = 180°

    m∠ADM = 180° - 144°

                   = 36°

e). m∠ADC = \frac{1}{2}(m\angle ADM)

                   = \frac{1}{2}(36)

                   = 18°

5 0
1 year ago
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