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GuDViN [60]
2 years ago
12

Statisticians for a roadside assistance company interviewed 50,000 randomly selected United States (US) households. Of those, 15

,595 reported that they had traveled 50 or more miles from home between December 23 and January 4. If there are 115,000,000 US households, approximately how many of them do the interviews suggest traveled 50 or more miles from home at that time?
Mathematics
1 answer:
I am Lyosha [343]2 years ago
8 0

Answer:

35,868,500 people

Step-by-step explanation:

#We calculate the probability of those who traveled 50+ miles.

-Probability is the likelihood of success. n=50000, p=15595:

P(X\geq 50)=\frac{15595}{50000}\\\\=0.3119

-The US population is 115000000. We determine what fraction of the actual population traveled 50+ miles:

E(X)=np, N=115000000,p=0.3119\\\\=0.3119\times 115000000\\\\\\=35868500

Hence, 35,868,500 people traveled 50+ miles.

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Answer:

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Step-by-step explanation:

Factor the following:

15 x^2 - 2 x - 8

Factor the quadratic 15 x^2 - 2 x - 8. The coefficient of x^2 is 15 and the constant term is -8. The product of 15 and -8 is -120. The factors of -120 which sum to -2 are 10 and -12. So 15 x^2 - 2 x - 8 = 15 x^2 - 12 x + 10 x - 8 = 5 x (3 x + 2) - 4 (3 x + 2):

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