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Alexeev081 [22]

2 years ago

10

I see that your new product is available for 412.50 on the website. How much is it if I buy it in the store? The website is a 25

%discount

1 answer:

OverLord2011 [107]2 years ago

3 0

Answer with explanation:

Price of Product on the Website = $ 412.50

It is given that, product is offered at a discount of 25% on the website.

Let actual price of product on the store = $ x

Writing the above statement in terms of equation

→Price at store - Discount= Price at Website

$x-\frac{25\times x}{100}=412.50\\\\ \frac{75 x}{100}=412.50\\\\x=\frac{41250}{75}\\\\x=550$

Price at store of that Product = $ 550

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Each vertical cross-section of the triangular prism shown below is an isosceles triangle.

vova2212 [387]

Answer:

Height is 3

Step-by-step explanation:

4.24 x 4.24 x 6

Right triangle base = a + b + c

a^2 + 3^2 = 4.24^2

= a^2 + 9 = 17.98

We cross out b to subtract.

a^2 = 17.98 - 9

a^2 = 8.98

We then square √a^2 = √8.98

a = 2.996

We round up a = 3

We have found the height is 3

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2 years ago

In ΔABC, and m∠ABC = 90°. D and E are the midpoints of and , respectively. If the length of is 9 units, the length of is units a

jok3333 [9.3K]

This is an isosceles right triangle (AB = BC & ∠ B=90° - Given)
Then the angles at the base are equal and ∠ CAB = ∠ ACB = 45°

Theorem: Segment DE, joining the midpoints of 2 sides is:
1st) parallel to the 3rd side and
2nd) equal to half the measurement of the 3rd side
So if the 3rd side (hypotenuse) = 9 units, DE = 9/2 = 4.5 units

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2 years ago

Match the following guess solutions ypyp for the method of undetermined coefficients with the second-order nonhomogeneous linear

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

1 ) Given that

$(d^2y/dx^2) + 4y = x - x^2 + 20\\\\ (d^2y/dx^2) + 4y = - x^2 + x + 20$

For a non homogeneous part $- x^2 + x + 20$ , we assume the particular solution is

$y_p(x) = Ax^2 + Bx + C$

2 ) Given that

$d^2y/dx^2 + 6dy/dx + 8y = e^{2x}$

For a non homogeneous part $e^{2x}$ , we assume the particular solution is

$y_p(x) = Ae^{2x}$

3 ) Given that

y′′ + 4y′ + 20y = −3sin(2x)

For a non homogeneous part −3sin(2x) , we assume the particular solution is

$y_p(x) = Acos(2x)+Bsin(2x)$

4 ) Given that

y′′ − 2y′ − 15y = 3xcos(2x)

For a non homogeneous part 3xcos(2x) , we assume the particular solution is

$y_p(x) = (Ax+B)cos2x+(Cx+D)sin2x$

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1 year ago

Mr. Itol's assistant takes twice as long to complete a computer task as Mr. Itol. If it takes both experts 6 hours to complete t

earnstyle [38]

His assistant would have to take 4 hour 30 minutes while Mr. Itol would take 1 hour 30 minutes.

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2 years ago

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If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.

fenix001 [56]

Given:

$h:k=2:5,x:y=3:4,2h+x:k+2y=1:2$

To find:

$h-x:k-y$

Solution:

We have, $h:k=2:5$ and $x:y=3:4$ .

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

$2h+x:k+2y=1:2$

It can be written as

$\dfrac{2h+x}{k+2y}=\dfrac{1}{2}$

$\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}$

$\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}$

$2(4a+3b)=1(5a+8b)$

On further simplification, we get

$8a+6b=5a+8b$

$8a-5a=8b-6b$

$3a=2b$

$a=\dfrac{2b}{3}$

Now,

$h-x:k-y=\dfrac{h-x}{k-y}$

$h-x:k-y=\dfrac{2-3b}{5a-4b}$

$h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}$

$h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}$

On further simplification, we get

$h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}$

$h-x:k-y=\dfrac{-5b}{-2b}$

$h-x:k-y=\dfrac{5}{2}$

$h-x:k-y=5:2$

Therefore, the ratio $h-x:k-y$ is $5:2$ .

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1 year ago