I see that your new product is available for 412.50 on the website. How much is it if I buy it in the store? The website is a 25
1 answer:
Answer with explanation:
Price of Product on the Website = $ 412.50
It is given that, product is offered at a discount of 25% on the website.
Let actual price of product on the store = $ x
Writing the above statement in terms of equation
→Price at store - Discount= Price at Website
Price at store of that Product = $ 550
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General Idea:
(i) Assign variable for the unknown that we need to find
(ii) Sketch a diagram to help us visualize the problem
(iii) Write the mathematical equation representing the description given.
(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE
Applying the concept:
Given: x represents the length of the pen and y represents the area of the doghouse
<u>Statement 1: </u>"The pen is 3 feet wider than it is long"
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<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>
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<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>
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<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>
Conclusion:
The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.
Answer:
If we solve for k we can do this:
So then we have at last 75% of the data withitn two deviations from the mean so the limits are:
Step-by-step explanation:
We don't know the distribution for the scores. But we know the following properties:
For this case we can use the Chebysev theorem who states that "At least of the values lies between
and
"
And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:
If we solve for k we can do this:
So then we have at last 75% of the data withitn two deviations from the mean so the limits are: