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Mazyrski [523]
2 years ago
9

If the area of the rectangle is given by the polynomial 2x^2-7x-15, what is the dimension of the reactangle in terms of x?​

Mathematics
1 answer:
Irina18 [472]2 years ago
4 0

Answer:

  • x - 5 and 2x + 3

Step-by-step explanation:

<h3>Given</h3>
  • Area of rectangle = 2x^2 - 7x - 15
<h3>To find</h3>
  • Dimensions of rectangle
<h3>Solution</h3>

<u>Since the area is the product of the sides, let's try to factorize the given:</u>

  • 2x^2 - 7x - 15=
  • 2x^2 - 10x + 3x - 15 =
  • 2x(x - 5) + 3(x - 5) =
  • (x - 5)(2x + 3)

<u>So the dimensions are:</u>

  • x - 5 and 2x + 3

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sergeinik [125]

Answer:

180^\circ C

Step-by-step explanation:

To convert from degree Fahrenheit to Celsius, we use the formula:

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If Habib's recipe is to be baked at 356 degree Fahrenheit, then we substitute F=356 to obtain an equivalent value in degree Celsius.

\text{Temperature in }^\circ C=\dfrac{5^\circ F-160}{9}\\=\dfrac{5*356-160}{9}\\=\dfrac{1780-160}{9}\\=\dfrac{1620}{9}\\\text{Temperature in }^\circ C=180^\circ C

Habib should bake his scones at 180^\circ C.

6 0
2 years ago
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An experiment was performed to compare the wear of two different laminated materials. Twelve pieces of material 1 were tested by
GenaCL600 [577]

Answer:

At 0.05 level of significance, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Step-by-step explanation:

We hypothesize that mean difference between abrasive wear of material 1 and material 2 is greater than 2.

So we write the null hypothesis H_0 : \mu_1 - \mu_2 >2,

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We will find the T-score as well as the p-value. If the p-value is less than the level of significance, we will reject the null hypothesis, i.e. we will conclude that the abrasive wear of material 1 is less than that of material 2. Otherwise, we will accept the null hypothesis.

Since the variance is unknown and assumed to be equal, we will use the pooled variance

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The mean of material 1 and material 2 are \mu_1 =85, \mu_2=81 respectively and mean difference d is equal to 4. The hypothesize difference d_0 is equal to 2.

To find the T-score, we use the following formula

T = \frac{d - d_0}{\sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2} }}

Substituting all the values into the T-score formula gives us T = 1.04, and the respective p-value is equal to 0.31. This means we have enough statistical evidence not to reject the null hypothesis, and at 5% significance level, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units.

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1 year ago
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gayaneshka [121]

Answer:

Step-by-step explanation:

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